If we draw the contingency table of x (vertical) against y (horiz.), we have a square.
For n=4, we have (legend: < : x<y = : x=y > : x>y
y 1 2 3 4
x
1 = < < <
2 > = < <
3 > > = <
4 > > > =
We see that there are n(n-1)/2 cases of x<y out of n^2.
Therefore,
p(x<y)=n(n-1)/(2n^2)=(n-1)/(2n)
However, if the sample space is continuous, it will be simply p(x<y)=1/2.
Given:
To find:
The 
.
Solution:
In circle B, 
is central angle and 
is inscribed angle from two points A and C.
According to central angle theorem, central angle is always twice of inscribed angle.
[Central angle theorem]
Divide both sides by 2.
Therefore, 
.
B if you’re doing distributive property
Step-by-step explanation:
Number of Combinations
= 25C0 + 25C1 + 25C2 + 25C3 + 25C4 + 25C5
= 1 + 25 + 300 + 2300 + 12650 + 53130
= 68,406.
There are a total of 68,406 combinations.
