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Oksana_A [137]
3 years ago
14

How many non-congruent triangles can you draw with the given properties? a. Sides measuring 7 inches, 8 inches, and 16 inches b.

Sides measuring 4 inches, 4 inches, and 6 inches c. Angles measuring 30°, 60°, and 90° d. Three angles measuring 120° e. Two angles measuring 45° and one side length measuring 10 inches
Mathematics
1 answer:
Leno4ka [110]3 years ago
6 0

Answer:

The answers are;

a. None

b. None

c. Infinite

d. None

e. None

Step-by-step explanation:

The number of non congruent triangles that can be drawn depends on the uniqueness of the triangle

The parameters of a unique triangle are;

Knowing the Side Side Side (SSS)

Knowing the Side Angle Side (SAS)

Knowing the Angle Side Angle (ASA)

Knowing the Angle Angle Side (AAS)

However, knowing only the Side Side Angle it is possible to draw two non-congruent triangles

Therefore, considering each of the triangles gives;

a. Sides 7 inches, 8 in., and 16 in. which is of the form SSS hence the triangle is well defined and it is not possible to draw two non-congruent triangle with the provided properties

b. Similarly, the given triangle parameters are 4 in., 4 in., and 6 in. which is of the form SSS hence the triangle is well defined and it is not possible to draw two non-congruent triangle with the provided information

c. The parameters of the triangle given here are angles 30°, 60°, and 90° which is of the form Angle Angle Angle, or AAA for which the sides can be scaled to form an infinite number of non-congruent triangles

d. The parameters given are three angles measuring 120° which does not form a triangle as the sum of triangles in a triangle = 180°

Hence the number of non-congruent triangles that can be drawn in this case = 0

e. The parameters given are two angles measuring 45° and one side length of 10 in., hence the parameter is of the forms AAS or ASA hence the triangle is unique and it is not possible to draw two non-congruent triangle with the provided properties.

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Step-by-step explanation:

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We can say the measure of angle E = 35 because the sum of angles in a triangle equal to 180

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What is the area of a rectangle with vertices at (4, 3), (11, 3), (11, 9), and (4, 9)?
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Answer:

The area of a rectangle is 42 units ².

Step-by-step explanation:

As the diagram is given below.

Distance Formula

Distance\ formula = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

As the rectangle with vertices at A (4, 3), B(11, 3),C (11, 9), and D (4, 9).

Take A (4, 3) to B(11, 3)

AB = \sqrt{(11-4)^{2}+(3-3)^{2}}

AB = \sqrt{(7)^{2}+(0)^{2}}

AB = \sqrt{49}

\sqrt{49} =7

AB = 7 units

As take B(11, 3) to C (11, 9).

BC = \sqrt{(11-11)^{2}+(9-3)^{2}}

BC = \sqrt{(0)^{2}+(6)^{2}}

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BC = 6 units

As take C (11, 9) toD (4, 9).

CD = \sqrt{(4-11)^{2}+(9- 9)^{2}}

CD = \sqrt{(7)^{2}+(0)^{2}}

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As take  D (4, 9) to  A (4, 3)

DA = \sqrt{(4-4)^{2}+(3-9)^{2}}

DA = \sqrt{(0)^{2}+(-6)^{2}}

DA = \sqrt{36}

\sqrt{36} =6

DA =  6 units

Thus

AB = DC= 7 units

AD = BC = 6 units

Formula

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Length = 7 units

Breadth = 6 units

Put value  in the above

Area of rectangle =  7 × 6  

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Therefore the area of a rectangle is 42 units ².

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