Answer:
(-3, 13)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Algebra I</u>
- Terms/Coefficients
- Coordinates (x, y)
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
y = -4x + 1
11y = x + 146
<u>Step 2: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitute in <em>y</em>: 11(-4x + 1) = x + 146
- Distribute 11: -44x + 11 = x + 146
- [Addition Property of Equality] Add 44x on both sides: 11 = 45x + 146
- [Subtraction Property of Equality] Subtract 146 on both sides: -135 = 45x
- [Division Property of Equality] Divide 45 on both sides: -3 = x
- Rewrite/Rearrange: x = -3
<u>Step 3: Solve for </u><em><u>y</u></em>
- Define original equation: y = -4x + 1
- Substitute in <em>x</em>: y = -4(-3) + 1
- Multiply: y = 12 + 1
- Add: y = 13
You can treat sq rt5 as a variable even though it is a number:
Ex: x + x = 2x
Or as a number: 5 + 5 = 10 or 2(5)
So sq rt5 + sq rt5 = 2sq rt5
The answer is 3/5.
...................................
Answer:
10
Step-by-step explanation:
4-1=3 (length of base)
-1-1=-2 (absolute value of height is 2)
3+2+2+3=10
Answer:
-2
Step-by-step explanation:
