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3 years ago

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Find mean, median, mode for the following. The following table of grouped data represents the weight (in pounds) of 100 Computer

towers Weight(in pounds). 3,4,5,6,7. Number of computers. 8,25,45,18,4

1 answer:

ExtremeBDS [4]3 years ago

5 0

Answer:

<em>A.(for weight in pounds)</em>

3, 4, 5, 6, 7

Median: 5

Mode: There are no mode in the following data set.

Mean: 3 + 4 + 5 + 6 + 7 = 25/5 = 25

<em>B.(for number of computers)</em>

4, 8, 18, 25, 45

Median: 18

Mode: There are no mode in the following data set.

Mean: 4 + 8 + 18 + 25 + 45 = 100/5 = 20

~hope this helps~

I would highly appreciate it if you b=would give me the brainliest~ :)

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The formula is m=4a+2c where c is the number of children, m=the number of meatballs, a=number of adults.

Trava [24]

Answer:

110

Step-by-step explanation:

m = 4a + 2c

a = 25, c = 5

m = 4(25) + 2(5)

m = 100 + 10

m = 110 meatballs

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3 years ago

The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?

Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$A(-6, 2)) = (x_1, y_1)$

$B(2, 6) = (x_2, y_2)$

$AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}$

$AB = \sqrt{(8)^2 + (4)^2}$

$AB = \sqrt{64 + 16} = \sqrt{80}$

$AB = 8.9$ (nearest tenth)

Distance between B(2, 6) and C(7, 1):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$B(2, 6) = (x_1, y_1)$

$C(7, 1) = (x_2, y_2)$

$BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}$

$BC = \sqrt{(5)^2 + (-5)^2}$

$BC = \sqrt{25 + 25} = \sqrt{50}$

$BC = 7.1$ (nearest tenth)

Distance between C(7, 1) and D(3, -5):

$CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$C(7, 1) = (x_1, y_1)$

$D(3, -5) = (x_2, y_2)$

$CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}$

$CD = \sqrt{(-4)^2 + (-6)^2}$

$CD = \sqrt{16 + 36} = \sqrt{52}$

$CD = 7.2$ (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

$DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$D(3, -5) = (x_1, y_1)$

$A(-6, 2) = (x_2, y_2)$

$DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}$

$DA = \sqrt{(-9)^2 + (7)^2}$

$DA = \sqrt{81 + 49} = \sqrt{130}$

$DA = 11.4$ (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

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3 years ago

In the given triangle ABC, find DE. answers: 20 5 10 2.5

adell [148]

Answer:

5

Step-by-step explanation:

Let's call the length AD y.

$\dfrac{x+2}{y}=\dfrac{8x-14}{2y} \\\\\\2(x+2)=8x-14 \\\\\\2x+4=8x-14 \\\\\\4=6x-14 \\\\\\6x=18 \\\\\\x=3 \\\\\\DE=x+2=3+2=5$

Hope this helps!

5 0

3 years ago

1/16^3x=64^2(x+8)<br> Solve for x.

SSSSS [86.1K]

Answer:

x = -4

Step-by-step explanation:

16 = 4*4 = 4²

64 = 4 * 4* 4 = 4³

$(\dfrac{1}{16})^{3x}=64^{2*(x+8)}\\\\\\(16^{-1})^{3x}=64^{2x + 16}\\\\\\16^{-3x}=64^{2x +16}\\\\(4^{2})^{-3x}=(4^{3})^{2x+16}\\\\4^{-6x}=4^{6x +48}$

As bases are same, compare exponents

6x + 48 = -6x

Subtract 48 from both sides

6x = -6x - 48

Add '6x' to both sides

6x + 6x = -48

12x = -48

Divide both sides by 12

x = -48/12

x = -4

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2 years ago

MSAL 1.1.PS-35 Question Help A fruit juice company includes 1.729 ounces of apple juice in a 6.55-ounce bottle of a mixed fruit

Alex777 [14]

Answer:

4.821 ounces

Step-by-step explanation:

To figure out the amount that is <em>not </em>apple juice, you have to subtract the amount of apple juice, 1.729 ounces, from the total amount of mixed fruit juice, 6.55 ounces, to get the remainder of 4.821 ounces.

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3 years ago