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BigorU [14]
3 years ago
6

Simplify. 3x(2x + 4y)

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
6 0
12xy+6x^2 is the expression 3x(2x+4y) simplified
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The length of a rectangular garden is 30 yards more than the width. The perimeter is 300 yards. Find the length and width
andre [41]

Answer:

60 yards

Step-by-step explanation:

300 = 2(30 + w) + 2(w)

300 = 60 +2w + 2w

300 = 60 + 4w

240 = 4w

60 = w

5 0
3 years ago
Use absolute value notation to represent the distance between x and 8 is no more than 4
ivanzaharov [21]
The distance: use absolute value
Between x and 8: x-8

The distance between x and 8: | x-8 |

“is no more than” means it can be that or be less than that, so use ≤

The distance between x and 8 is no more than 4

| x-8 | ≤ 4
3 0
3 years ago
Step 3a: Calculating the average rate
Alex73 [517]

9514 1404 393

Answer:

  a) average rate = (total distance)/(total time)

  b) Rave = 2·R1·R2/(R1 +R2)

  c) cheetah's average rate ≈ 50.91 mph

Step-by-step explanation:

a) Let AB represent the distance from A to B. Let t1 and t2 represent the travel times (in hours) on leg1 and leg2 of the trip, respectively. Then the distances traveled are...

  First leg distance: AB = 70·t1   ⇒   t1 = AB/70

  Second leg distance: AB = 40·t2   ⇒   t2 = AB/40

The average rate is the ratio of total distance to total time:

  average rate = (AB +AB)/(t1 +t2)

  average rate = 2AB/(AB/70 +AB/40) = 2/(1/70 +1/40) = 2(40)(70)/(70+40)

  average rate = 560/11 = 50 10/11 . . . mph

__

No equations are given, so we cannot compare what we wrote with the given equations. In each step of the solution, we have used the rules of algebra and equality.

b) For two rates over the same distance (as above), the average is their harmonic mean:

  average rate = 2r1·r2/(r1+r2)

__

c) The cheetah's average rate was 50 10/11 mph ≈ 50.91 mph.

4 0
3 years ago
In the year 2005, a total of 750 fish were introduced into a manmade lake. The fish population was expected to grow at a rate of
tangare [24]
The population of the fish is given by P(t) = 750(1 + 0.083)^t; where t is the number of years after 2005.
Here, t = 2050 - 2005 = 45

Population in 2050 = 750(1.083)^45 = 750(36.16) = 27,123
8 0
3 years ago
Read 2 more answers
Please hellpppppppppppppppppppppp!
a_sh-v [17]

Answer:

x=

​

≈0.111111111

Step-by-step explanation:

7 0
2 years ago
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