What is x^2+6x=x^2-6x as a system?

Gordon types 2,736 words in 36 minutes. Find the unit rate.

STALIN [3.7K]

Answer:

76 words each minute

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

If anyone could solve this question for me while showing the steps. It would be GREATLY appreciated

Blizzard [7]

this is a very annoying problem, with lots of steps. it is on a next level of dragging on and on

Step-by-step explanation:

You can split this into different shapes. A triangle, a rectangle, and a void of a quarter circle. The total area is rectangle+triangle-quarter circle.

We find the second side of the triangle by doing 65-48=17

We then use the pythagorean theorem to find the third length. This is about 49.1426.

We can then use whatever method you'd like for finding the area of the triangle. it turns out to be about 417.7125

Next, we find the rectangle, easy enough, 49.1426*48=2358.8448

which seems a bit scuffed until you realize that the diagram itself is scuffed as well. Great, quarter circle next

16*16*pi/4=201.0619

Alright, now to combine it to find the area.

417.7125+2358.8448-201.0619=2575.4954

great, now let's find the perimeter, simple enough. Curved perimeter+straight perimeter-that one corner in the bottom right

52+48+49.1426+65-32+25.1327=207.2753

and now we convert to meters

207.2753feet=63.1775meters

We are almost done! Now let's find the cost.

Fencing first:

63.1775*8.50=537.01

Then the cement

2575.4954*5.50=14165.2247

Then we add it up and apply tax:

537.01+14165.2247=14702.2347

14702.23*1.13=$16613.53

if you find anything wrong message me, I may have made errors because its 10pm and i need sleep. I recommend you work through my steps on your own as well. There might be complications with rounding as well, so yea. Hope this helps!

3 0

1 year ago

Find the length of a diagonal of a rectangle if the length of the rectangle is 24 cm and its width is 10 cm. A) 22 cm B) 26 cm C

Alik [6]

Your answers are
1.B
2.D
3.A

3 0

2 years ago

Read 2 more answers

Evaluate 12 x (4^-2/4^-4) A 1/4 B 3/4 C 16 D 192

MrMuchimi

12 ×4^4/4^2
=12×4^2
=12×16
=192

7 0

3 years ago

How do I solve: 2 sin (2x) - 2 sin x + 2√3 cos x - √3 = 0

ziro4ka [17]

Answer:

$\displaystyle x = \frac{\pi}{3} +k\, \pi$ or $\displaystyle x =- \frac{\pi}{3} +2\,k\, \pi$ , where $k$ is an integer.

There are three such angles between $0$ and $2\pi$ : $\displaystyle \frac{\pi}{3}$ , $\displaystyle \frac{2\, \pi}{3}$ , and $\displaystyle \frac{4\,\pi}{3}$ .

Step-by-step explanation:

By the double angle identity of sines:

$\sin(2\, x) = 2\, \sin x \cdot \cos x$ .

Rewrite the original equation with this identity:

$2\, (2\, \sin x \cdot \cos x) - 2\, \sin x + 2\sqrt{3}\, \cos x - \sqrt{3} = 0$ .

Note, that $2\, (2\, \sin x \cdot \cos x)$ and $(-2\, \sin x)$ share the common factor $(2\, \sin x)$ . On the other hand, $2\sqrt{3}\, \cos x$ and $(-\sqrt{3})$ share the common factor $\sqrt[3}$ . Combine these terms pairwise using the two common factors:

$(2\, \sin x) \cdot (2\, \cos x - 1) + \left(\sqrt{3}\right)\, (2\, \cos x - 1) = 0$ .

Note the new common factor $(2\, \cos x - 1)$ . Therefore:

$\left(2\, \sin x + \sqrt{3}\right) \cdot (2\, \cos x - 1) = 0$ .

This equation holds as long as either $\left(2\, \sin x + \sqrt{3}\right)$ or $(2\, \cos x - 1)$ is zero. Let $k$ be an integer. Accordingly:

$\displaystyle \sin x = -\frac{\sqrt{3}}{2}$ , which corresponds to $\displaystyle x = -\frac{\pi}{3} + 2\, k\, \pi$ and $\displaystyle x = -\frac{2\, \pi}{3} + 2\, k\, \pi$ .
$\displaystyle \cos x = \frac{1}{2}$ , which corresponds to $\displaystyle x = \frac{\pi}{3} + 2\, k \, \pi$ and $\displaystyle x = -\frac{\pi}{3} + 2\, k \, \pi$ .

Any $x$ that fits into at least one of these patterns will satisfy the equation. These pattern can be further combined:

$\displaystyle x = \frac{\pi}{3} + k \, \pi$ (from $\displaystyle x = -\frac{2\,\pi}{3} + 2\, k\, \pi$ and $\displaystyle x = \frac{\pi}{3} + 2\, k \, \pi$ , combined,) as well as
$\displaystyle x =- \frac{\pi}{3} +2\,k\, \pi$ .

7 0

3 years ago