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3 years ago

8

Which of the following is the reciprocal of x2-2x-8

1 answer:

Lemur [1.5K]3 years ago

4 0

It would be 1 / (x + 2) (x - 4)

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Convert the angle theta=7/4pi radians to degrees

bagirrra123 [75]

7/4pi multiplied by 180/pi give you about 97 degrees when you calculate it.

7 0

3 years ago

Help please I have a test tomorrow!!!!

Taya2010 [7]

For find f(-2) of f(x)=7x+3, plug in -2 for x.
7(-2)+3=y
-14+3=y
y=-11
To find the rate, or the slope, you divide x/y. So 2/6 is 1/3. 3 over 9 is also 1/3. So the rate is 1/3. In rates you always divide, you don't mulitply or subtract or add to find the rate.

6 0

2 years ago

You wish to create a 5 digit number from all digits; 0 1 2 3 4 5 6 7 8 9

NNADVOKAT [17]

Answer:

10234

Step-by-step explanation:

one is the smallest number so its first

and then you can place zero

after that just place the second smallest number

and so on

5 0

2 years ago

Given the following functions, find each of the values:

allsm [11]

The function is computed below based on the information. The answers will be:

1. -11

2. -1

<h3>How to compute the function?</h3>

f(x) = x²-11x+28

g(x) = x-4

(f+g)(-5) = (-5² - 11 × 5 + 28) + (-5 - 4)

= 25 - 55 + 28 - 9

= -11

(f-g)(5)

= = (5² - 11 × 5 + 28) + (5 - 4)

= 25 - 55 + 28 + 1

= -1

Learn more about functions on:

brainly.com/question/25638609

#SPJ1

4 0

9 months ago

Solve the initial value problem y'=2 cos 2x/(3+2y),y(0)=−1 and determine where the solution attains its maximum value.

zloy xaker [14]

Answer:

$y=\frac{-3\pm\sqrt{4sin2x+1}}{2}$

$x={\pi}{4}$

Step-by-step explanation:

We are given that

$y'=\frac{2cos2x}{3+2y}$

y(0)=-1

$\frac{dy}{dx}=\frac{2cos2x}{3+2y}$

$(3+2y)dy=2cos2x dx$

Taking integration on both sides then we get

$\int (3+2y)dy=2\int cos 2xdx$

$3y+y^2=sin2x+C$

Using formula

$\int x^n=\frac{x^{n+1}}{n+1}+C$

$\int cosx dx=sinx$

Substitute x=0 and y=-1

$-3+1=sin0+C$

$-2=C$

$sin0=0$

Substitute the value of C

$y^2+3y=sin2x-2$

$y^2+3y-sin 2x+2=0$

$y=\frac{-3\pm\sqrt{(3)^2-4(1)(-sin2x+2)}}{2}$

By using quadratic formula

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$y=\frac{-3\pm\sqrt{9+4sin2x-8}}{2}=\frac{-3\pm\sqrt{4sin2x+1}}{2}$

Hence, the solution $y=\frac{-3\pm\sqrt{4sin2x+1}}{2}$

When the solution is maximum then y'=0

$\frac{2cos2x}{3+2y}=0$

$2cos2x=0$

$cos2x=0$

$cos2x=cos\frac{\pi}{2}$

$cos\frac{\pi}{2}=0$

$2x=\frac{\pi}{2}$

$x=\frac{\pi}{4}$

3 0

3 years ago