is continuous on [0, 3] and differentiable on (0, 3), so the mean value theorem applies here. It says that there is some
in the open interval (0, 3) such that
We have
so
Is it an irrational numbet
1 answer:
You might be interested in
Hi there!
Using the equation for the area of a circle, we can simply substitute pi with its numerical value of 3.14 and r with the radius given.
1.) Area = (3.14)(6cm)² = 113.0 cm²
2.) Area = (3.14)(28in)² = 2461.8 in²
3.) To find radius, first we must divide the diameter in half. So, 11/2 = 5.5 ft
Area = (3.14)(5.5ft)² = 95 ft²
4.) Similar to 3, to find radius, first we must divide the diameter in half. So, 10.5/2 = 5.25 in
Area = (3.14)(5.25in)² = 86.5 in²
5.) Area = (3.14)(6.3mm)² = 124.6 mm²
6.) Area = (3.14)(3
yd)² = 33.2 yd²
Using the equation for the area of a circle, we can simply substitute pi with its numerical value of 3.14 and r with the radius given.
1.) Area = (3.14)(6cm)² = 113.0 cm²
2.) Area = (3.14)(28in)² = 2461.8 in²
3.) To find radius, first we must divide the diameter in half. So, 11/2 = 5.5 ft
Area = (3.14)(5.5ft)² = 95 ft²
4.) Similar to 3, to find radius, first we must divide the diameter in half. So, 10.5/2 = 5.25 in
Area = (3.14)(5.25in)² = 86.5 in²
5.) Area = (3.14)(6.3mm)² = 124.6 mm²
6.) Area = (3.14)(3
Answer:
A.
B.
C.
Step-by-Step Explanation:
A. Tangent to x-axis, r=4, contains (-5,8)
The equation of a circle is this:
Therefore, we know that our equation will be:
Because the circle is tangent to the x-axis, the point (-5,8) will be the top of the circle.
Therefore, the center is (-5,4), where -5=h and 4=k.
The answer is
B. Diameter endpoints (2,5) and (0,3)
To solve for the diameter, we can use this equation:
Because the radius is half of the diameter,
Therefore, we know that our equation will be:
Then, we can decipher that h=1, as the midpoint of 0 and 2 is 1, and k=4, as the midpoint of 3 and 5 is 4.
The answer is
C. Center on x=3, tangent to y-axis at (0,5)
We can see that the center is (3,5). Therefore, the equation is
To solve for r, we can substitute the point (0,5) into the equation.
The answer is
<em>Hope this helped!</em>
