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4 years ago

Help with number 5 please

Mathematics

1 answer:

DanielleElmas [232]4 years ago

6 0

A is 7 & 7/8. B is correct. C is 1 & 1/4. They are all in simplest form, also.

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Evaluate 8-m/m+p3 when m=8 n=2 p=7

seropon [69]

Answer:

Step-by-step explanation:

8 - 8 / 8 + 7 *3

PEMDAS

8 - 1 * 7 - 3

8 - 1 + 21

3 0

3 years ago

Use a math drawing to explain why LaTeX: \frac{4}{5}=\frac{4\:\times3}{5\:\times3}\:=\frac{12}{15}4 5 = 4 × 3 5 × 3 = 12 15 .

Arte-miy333 [17]

Answer:

....................

6 0

3 years ago

For which of the following compound inequalities is there no solution? Select one: a. 8m+5>=5 and -4m+6<=-10 b. 6m<=-36

enyata [817]

$a.\\8m+5\geq5\
\ \ |-5\\8m\geq0\ \ \ |:8\\m\geq0\to m\in\left$

$b.\\6m\leq-36\ \ \ |:6\\m\leq-6\to m\in\left(-\infty;\
-6\right>\\\\m+24 > 20\ \ \ |-24\\m > -4\to m\in(-4;\
\infty)\\\\solution:\ m\in\left(-\infty;\ -6\right>\ \cap\ (-4;\ \infty)\to
m\in\O\to NO\ SOLUTION$

$c.\\-2m < 6\ \ \ |:(-2)\\m > -3\to m\in(-3;\ \infty)\\\\3m > 24\
\ \ |:3\\m > 8\to m\in(8;\ \infty)\\\\solution:\ m\in(-3;\ \infty)\ \cap\
(8;\ \infty)\to m\in(8;\ \infty)$

$d.\\m+9 < 8\ \ \ |-9\\m < -1\to m\in(-\infty;\ -1)\\\\-2m \geq10\ \
\ |:(-2)\\m\leq-5\to m\in\left(-\infty;-5\right>\\\\solution:\
m\in(-\infty;\ -1)\ \cap\ \left(-\infty;-5\right>\to
m\in\left(-\infty;-5\right>$

6 0

4 years ago

If john had 9 apples and pickles gave him ten more how much apples does John have? (9+10)

Rzqust [24]

Answer:

but if ur serius then 19

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

In a right triangle, the length of the hypotenuse is 12 and the measure of one of the angles is 36. What is the length of the ot

DochEvi [55]

Answer:

Either 9.71 (adjacent to 36°) or 7.05 (opposite 36°)

Step-by-step explanation:

The question doesn't specify which leg is under question. Is it the adacent leg or the opposite leg? I'll assume adjacent.

We can use the acronym

SOHCAHTOA which is a helpful mnemonic for remembering the definitions of the trigonometric functions. For an angle other than the right angle, the following relationships are defined.

SOH: S is sine = Opposite/Hypotenuse

CAH: C is cosine = Adjacent/Hypotenuse

TOA: T is tangent = Opposite/Adjacent

For a side adjacent (A) to the 36° angle, we can use

Cosine = Adjacent/Hypotenuse

Since we know the hypotenuse (12) we can find A:

Cosine(36) = A/12

A = Cosine(36)*12

A = (0.809)*12

Adjacent = 9.71

====================

If the opposite leg is calculated, we would use

Sine= Opposite/Hypotenuse

Sine(36) = Opposite/12

O = (0.5877)*12

Opposite = 7.053

5 0

2 years ago