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Rasek [7]
3 years ago
9

Two quadratic functions are shown.

Mathematics
2 answers:
IrinaK [193]3 years ago
7 0
Function 1 written in vertex form is 4(x + 1)^2 - 3 meaning that the vertex is (-1, -3)
Function 2 has a vertex of (-1, 0)
Therefore, function 1 has the least minimum value with cordinates (-1, -3)
Ad libitum [116K]3 years ago
5 0

Answer:

The least minimum value is attained by:

First function---- f(x)

Coordinate of the point: (-1,-3)

Step-by-step explanation:

We are given a equation of first function as:

f(x)=4x^2+8x+1

The graph of this function is a parabola which is open upward and the vertex of the parabola is at (-1,-3)

Since, the parabola is open upward hence the vertex of the parabola is the point of minima of the parabola.

                 The minimum value of the function f(x) is:

                                   -3

Now we are given a table of values of the second  function i.e. g(x) as:

                          x    g(x)

                        −2     2

                        −1     0

                         0     2

                         1      8

Clearly by looking at the values we see that:

      The minimum value attained by the function g(x) is:

                                         0

The least minimum value is attained by:

First function--- f(x)

The coordinates of the minimum point are:  (-1,-3)

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Answer:

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Step-by-step explanation:

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If f(x) = 4 – x2 and g(x) = 6x, which expression is equivalent to (g – f)(3)?
Kryger [21]

For this case we have the following functions:

f (x) = 4 - x ^ 2\\g (x) = 6x

The first thing we must do for this case is to subtract both functions.

We have then:

(g - f) (x) = g (x) - f (x)

Substituting we have:

(g - f) (x) = (6x) - (4 - x ^ 2)

Rewriting we have:

(g - f) (x) = x ^ 2 + 6x - 4

Evaluating the obtained function for x = 3 we have:

(g - f) (3) = (3) ^ 2 + 6 (3) - 4\\(g - f) (3) = 23

Answer:

The value of the function evaluated at x = 3 is:

(g - f) (3) = 23

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