Answer:
(a). 72.9%.
(b). 13.6 hr.
Step-by-step explanation:
So, we are given the following data or parameters or information which is going to assist us in solving this question/problem;
=> "A welder produces 7 welded assemblies during the first day on a new job, and the seventh assembly takes 45 minutes (unit time). "
=> The worker produces 10 welded assemblies on the second day, and the 10th assembly on the second day takes 30 minutes"
So, we will be making use of the Crawford learning curve model.
T(7) + 10 = T (17) = 30 min.
T(7) = T1(7)^b = 45.
T(17 ) = T1(17)^b = 30.
(T1) = 45/7^b = 30/17^b.
45/30 = 7^b/17^b = (7/17)^b.
1.5 = (0.41177)^b.
ln 1.5 = b ln 0.41177.
0.40547 = -0.8873 b.
b = - 0.45696.
=> 2^ -0.45696 = 0.7285.
= 72.9%.
(b). T1= 45/7^ - 045696 = 109.5 hr.
V(TT)(17) = 109.5 {(17.51^ - 0.45696 – 0.51^ - 0.45696) / (1 - 0.45696)} .
V(TT) (17) = 109.5 {(4.7317 - 0.6863) / 0.54304} .
= 815.7 min .
= 13.595 hr.
Answer:
The value of H is (1/3)
Step-by-step explanation:
i found it by dividing the value of G on 2
Answer:
The correct answer is 0.15
Step-by-step explanation:
According to the given scenario, the probability is as follows:
X
Bin (n,p)
Here
n = 8
p = 0.20 or 20%
Now this is a binomial probability distribution
= 0.15
Hence, the correct answer is 0.15
9514 1404 393
Answer:
- Tyler
- 2 hundredths of a mile
Step-by-step explanation:
The graph is a little difficult to read, but we note that there are 6 grid lines between times that are 2 minutes apart. So, each grid line stands for 2/6 = 1/3 minute.
At the 1-mile mark, the graph crosses 1 grid line above 8 minutes, indicating it takes Tyler 8 1/3 minutes to run 1 mile.
Then in 10 minutes, Tyler will run ...
distance = speed · time = 1 mile/(8 1/3 min) · 10 min
= 1/(25/3)·10 = 10·3/25 = 30/25 = 1.2 . . . . miles
__
The equation tells you that Elena runs each mile in 8.5 minutes. To see how far she runs in 10 minutes, we can solve ...
10 = 8.5x
x = 10/8.5 ≈ 1.18 . . . . miles
So, Tyler runs farther in 10 minutes by a distance of ...
1.20 -1.18 = 0.02 . . . . miles
Answer:
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