Answer:
A. 5.16 s.
B. 5.66 s.
Step-by-step explanation:
A.
For a simple harmonic motion,
T = 2pi (sqrt * (l/g))
Given:
L1 = 3 cm
T1 = 4 s
L2 = 5 cm
T2 = ?
4 = 2pi*sqrt(3/g)
g = 7.4
At, L2,
T2 = 2pi*sqrt(5/7.4)
= 5.16 s.
B.
M1 = M1
M2 = 2*M1
For a simple harmonic motion,
T = 2pi (sqrt * (m/k))
4 = 2pi (sqrt * (M1/k))
M1/k = 0.405
Inputting the above values,
T2 = 2pi (sqrt * (2*M1/k))
= 2pi (sqrt * (2 * 0.405))
= 5.66 s.
Answer:
19.6 cm²
Step-by-step explanation:
If a circle fits perfectly inside of a square, then its diameter is equal to the length of sides of the square.
The area of a circle is given by:

In this problem, d = 5 cm, the area of the circle is:

The approximate area of the circle is 19.6 cm².
All real numbers greater than or equal to -3
Answer:
7y=x
Step-by-step explanation: