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mario62 [17]
3 years ago
11

Evaluate the expression 3÷1 1/5+1/2

Mathematics
1 answer:
Soloha48 [4]3 years ago
8 0
 61
----
110

The answer is 61 over 110, hope this helped you.

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Helppppppp! 15 points!
Vika [28.1K]

{\boxed{\mathcal{\purple{D.\:81}}}} ✅

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}

( {3})^{ \frac{11}{5} }  \div  {3}^{ \frac{ - 9}{5} }  \\  \\=(  {3})^{ \frac{11}{5} - ( \frac{ - 9}{5} ) }  \\ \\ = ( {3})^{ \frac{11}{5}   +  \frac{9}{5} }  \\ \\ = ( {3})^{ \frac{11 + 9}{5} } \\ \\  = ( {3})^{ \frac{20}{5} }  \\ \\  = ( {3})^{4}  \\ \\ = ( \: 3 \times 3 \times 3 \times 3 \: ) \\ \\ = 81

<u>Note</u>:-

{a}^{m}  \div  {a}^{n}  =  {a}^{m - n}

\sf\red{(-)\:x\:(-)\:=\:+}

\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{!}}}}}

4 0
3 years ago
Use a separate sheet of paper to solve the system of inequalities by graphing. Use the graph to decide if the point (1, –1) is i
Lena [83]

Answer:

The answer is no though, the point (1,-1) is below both.

Step-by-step explanation:

So the two inequalities are y≤-3x+3 and 3x+8y≥3

With inequalities you have to know a few things.  First, when you graph you may have to use non solid lines.  for instance, if you had x<5, 5 would not be part of the answer because it is only answers less than 5.  so you represent this by making a dashed line that says "you cannot include values on this line".  Second, with algebra, if you multiply both sides by a negative it flips the inequality.  for instance -y > 54 you would multiply (or divide) by -1 and it would change to y < -54.  Third, when graphing an inequality, treat it like an equation and graph the line as if it were said equation(with solid or dashed lines as needed)  then, if it is y > f(x) you shade in the section above the line and y < f(x) shades in below.  The shaded part is your answer basically.  Now lets get into yours.

y≤-3x+3

It is already in the form y = f(x)  so grapht he line 3x + 3 with a solid line since it is y is less than or equal to,  then shade below that line.  

3x+8y≥3

First get it so y is by itself

3x+8y≥3

8y≥3 - 3x

y ≥ 3/8 - 3/8 x

Now grapht his line  with a solid line and shade the area above it.

Now, the shaded area below between y ≥ 3/8 - 3/8 x and  y≤-3x+3 and the lines are your answer, so you need to check if the point (1, -1) is in this shared shaded area or on one of the lines.

The answer is no though, the point (1,-1) is below both.

6 0
3 years ago
4h+6+30 i need help with the problem
stira [4]
Result: 4h+36 

Geometric figure: Line 

Alternate form: 4(h+9) 

Root: h= -9 
7 0
3 years ago
Read 2 more answers
Find the length of the curve given by ~r(t) = 1 2 cos(t 2 )~i + 1 2 sin(t 2 ) ~j + 2 5 t 5/2 ~k between t = 0 and t = 1. Simplif
xxMikexx [17]

Answer:

The length of the curve is

L ≈ 0.59501

Step-by-step explanation:

The length of a curve on an interval a ≤ t ≤ b is given as

L = Integral from a to b of √[(x')² + (y' )² + (z')²]

Where x' = dx/dt

y' = dy/dt

z' = dz/dt

Given the function r(t) = (1/2)cos(t²)i + (1/2)sin(t²)j + (2/5)t^(5/2)

We can write

x = (1/2)cos(t²)

y = (1/2)sin(t²)

z = (2/5)t^(5/2)

x' = -tsin(t²)

y' = tcos(t²)

z' = t^(3/2)

(x')² + (y')² + (z')² = [-tsin(t²)]² + [tcos(t²)]² + [t^(3/2)]²

= t²(-sin²(t²) + cos²(t²) + 1 )

................................................

But cos²(t²) + sin²(t²) = 1

=> cos²(t²) = 1 - sin²(t²)

................................................

So, we have

(x')² + (y')² + (z')² = t²[2cos²(t²)]

√[(x')² + (y')² + (z')²] = √[2t²cos²(t²)]

= (√2)tcos(t²)

Now,

L = integral of (√2)tcos(t²) from 0 to 1

= (1/√2)sin(t²) from 0 to 1

= (1/√2)[sin(1) - sin(0)]

= (1/√2)sin(1)

≈ 0.59501

8 0
3 years ago
Write the equation in slope-intercept form ,of the line that passes through the given point and is parallel to the given line
Marrrta [24]
1/3x-1 I believe is the answer
5 0
3 years ago
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