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4 years ago

10

How do you make a fortune teller

1 answer:

Oduvanchick [21]4 years ago

4 0

This is the math section but ok
if yo mean the pyramid shaped thingie then

get a square piece of paper (4 right angles, equal length sides)
fold the paper in half so one corner touches the opposite corner
unfold
repeat but with the other corner that doesn't ahve a crease
unfold
you should have an x in the middle of the paper with 2 valleys facing up
now fold the 4 corners to the middle of the x so you have a smaller square now
flip it over so the flat side is facing you
fold the 4 corners in to the center
fold the square into a valley horizontally
unfold
fold the square into a valley vertically
unfold
flip it over and pry out the 4 corners and manipulate it like in the illustration

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Brianna earned $28,000 last year. If the first $20,000 is taxed at 10% and income above that is taxed at 13%, how much does Bria

DiKsa [7]

Answer:

3,040$

Step-by-step explanation:

20k*.1=2,000

8k*.13=1,040

2,000+1,040=3,040

I am so sorry if I'm wrong.

4 0

3 years ago

Read 2 more answers

Give the value of x .<br><br> A. 60 degrees<br> B. 180 degrees<br> C. 120 degrees<br> D. 45 degrees

Harrizon [31]

Answer:

x=120°

Step-by-step explanation:

sum of all angles in a triangle is equal to 180

let the unknown angle be

$\alpha$

$60 + 60 + \alpha = 180 \\ \alpha = 180 - 60 - 60 \\ \alpha = 60 \\$

$\alpha + x = 180 \\ x = 180 - \alpha \\ x = 180 - 60 \\ x = 120$

5 0

2 years ago

Which expression is equivalent to (16 x Superscript 8 Baseline y Superscript negative 12 Baseline) Superscript one-half?.

loris [4]

To solve the problem we must know the Basic Rules of Exponentiation.

<h2>Basic Rules of Exponentiation</h2>

$x^ax^b = x^{(a+b)}$
$\dfrac{x^a}{x^b} = x^{(a-b)}$
$(a^a)^b =x^{(a\times b)}$
$(xy)^a = x^ay^a$

$x^{\frac{3}{4}} = \sqrt[4]{x^3}= (\sqrt[3]{x})^4$

The solution of the expression is $\dfrac{4x^4}{y^6}$ .

<h2>Explanation</h2>

Given to us

$(16x^8y^{12})^{\frac{1}{2}}$

Solution

We know that 16 can be reduced to $2^4$ ,

$=(2^4x^8y^{12})^{\frac{1}{2}}$

Using identity $(xy)^a = x^ay^a$ ,

$=(2^4)^{\frac{1}{2}}(x^8)^{\frac{1}{2}}(y^{12})^{\frac{1}{2}}$

Using identity $(a^a)^b =x^{(a\times b)}$ ,

$=(2^{4\times \frac{1}{2}})\ (x^{8\times\frac{1}{2}})\ (y^{12\times{\frac{1}{2}}})$

Solving further

$=2^2x^4y^{-6}$

Using identity $\dfrac{x^a}{x^b} = x^{(a-b)}$ ,

$=\dfrac{2^2x^4}{y^6}$

$=\dfrac{4x^4}{y^6}$

Hence, the solution of the expression is $\dfrac{4x^4}{y^6}$ .

Learn more about Exponentiation:

brainly.com/question/2193820

8 0

2 years ago

HELP! SSUUUUUUUUPER EASY! REEEEEEEEEEEALLY QUICK! I'm just du. mb

pishuonlain [190]

the answer is 15m^6

7 0

2 years ago

Read 2 more answers

Simplify (3x - 5) - (5x + 1).<br> 0-2x + 6<br> -2x - 6<br> 2x - 6<br> 2x + 6<br> fast please!

mamaluj [8]

-2x-6

EXPLANATION

(3x-5) = (-2x) - 6

3 0

3 years ago