All categories

3 years ago

Find the equation for the line that passes through the point (1,−4) and that is parallel to the line with the equation y=4.

Mathematics

1 answer:

diamong [38]3 years ago

6 0

Answer:

y = -4.

Step-by-step explanation:

The line with equation y = 4 is a horizontal line on the coordinate plane which passes through the y-axis at y = the point (0, 4).

The other line parallel to this must also be horizontal and , as it passes through the point (1 , -4), must also pass through the y-axis at ( 0, -4). The equation of this line is y = -4.

You might be interested in

Assume that there is a 8% rate of disk drive failure in a year. a. If all your computer data is stored on a hard disk drive wit

romanna [79]

Answer:

0.9936 = 99.36% probability that during a year, you can avoid catastrophe with at least one working drive

Step-by-step explanation:

For each disk, there are only two possible outcomes. Either it works, or it does not. The probability of a disk working is independent of any other disk, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Assume that there is a 8% rate of disk drive failure in a year.

So 100 - 8 = 92% probability of working, which means that $p = 0.92$

Two disks are used:

This means that $n = 2$

What is the probability that during a year, you can avoid catastrophe with at least one working drive?

This is:

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{2,0}.(0.92)^{0}.(0.08)^{2} = 0.0064$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0064 = 0.9936$

0.9936 = 99.36% probability that during a year, you can avoid catastrophe with at least one working drive

8 0

3 years ago

THIS IS THE LAST QUESTION IDK HOW DO SOLVE IT :(

harkovskaia [24]

Answer:

6 laps.

Step-by-step explanation:

On Monday she runs 2x + 8 miles, where x miles = the length of the trail.

On Tuesday she runs 4x + 4 miles and this is the same distance as Monday, so

2x + 8 = 4x + 4

4 = 2x

x = 2 miles which is the length of the trail.

So each day she runs 4(2) + 4 = 12 miles.

So on Saturday she runs 12/ 2 = 6 laps.

4 0

3 years ago

Graph the solution of the inequality –3(x + 1) ≤ 6 on the number line.

fomenos

First you solve the inequality. Add the variables that can be added together. That would be -3 + 1=2. Now the equation is 2 + x<6. After you change the 2 into a negative and put it under the 6 and subtract. that is 3. 3 is the number you put on the number line. When you fine and plot three you make a dot above it. You fill in the dot since the less then sign has a line beneath it. Then you draw a line from the dot to the end of the number line from the direction the sign is facing. It’s a less then sign, so you would draw the line to the left.

3 0

3 years ago

As part of a screening process, computer chips must be operated in an oven at 145 °C. Ten minutes after starting, the temperatur

Novosadov [1.4K]

Answer:

Step-by-step explanation:

I solved this using initial conditions and calculus, so I hope that's what you are doing in math. It's actually NOT calculus, just a concept that is taught in calculus.

The initial condition formula we need is

$y=Ce^{kt}$

Filling in our formula with the 2 conditions we are given:

$65=Ce^{10k}$ and $85=Ce^{15k}$

With those 2 equations, we have 2 unknowns, the C (initial value) and the k (the constant). We know that the initial value (or starting temp) for both conditions is the same, so we solve for C in one equation, sub it into the other equation and solve for k. If

$65=Ce^{10k}$ then

$\frac{65}{e^{10k}}=C$ which, by exponential rules is the same as