surface area (S) of a right rectangular solid is:
S = 2*L*W + 2*L*H + 2*W*H (equation 1)
where:
L = length
W = width
H = height
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you have:
L = 7
W = a
H = 4
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formula becomes:
S = 2*7*a + 2*7*4 + 2*a*4
simplify:
S = 14*a + 56 + 8*a
combine like terms:
S = 22*a + 56
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answer is:
S = 22*a + 56 (equation 2)
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to prove, substitute any value for a in equation 2:
let a = 15
S = 22*a + 56 (equation 2)
S = 22*15 + 56
S = 330 + 56
S = 386
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since a = 15, then W = 15 because W = a
go back to equation 1 and substitute 15 for W:
S = 2*L*W + 2*L*H + 2*W*H (equation 1)
where:
L = length
W = width
H = height
-----
you have:
L = 7
W = 15
H = 4
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equation 1 becomes:
S = 2*7*15 + 2*7*4 + 2*15*4
perform indicated operations:
S = 210 + 56 + 120
S = 386
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surface area is the same using both equations so:
equations are good.
formula for surface area of right rectangle in terms of a is:
S = 22*a + 56
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Answer:
There are no values of x that make the equation true
The system has no solution
Step-by-step explanation:
we have
Solve for x
Subtract x both sides
-----> is not true
therefore
Is a inconsistent system
There are no values of x that make the equation true
The system has no solution
Sqr root of 56 - sqr root of 14 + sqr root of 126= sqr root of (4x14) - sqr root of 14 + sqr root of (9x14)= 2(sqr root of 14) - (sqr root of 14) + 3(sqr root of 14)= 4(sqr root of 14)
The right answer will be B.
To solve, divide by 7.
-2 < x < 3
The graph is a number line with open circles at -2 and 3 and a solid line between them.
