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const2013 [10]
3 years ago
15

A water taxi travels around an island in a path that can be modeled by the equation y =0.5(x - 16). A water skier is skiing alon

g a path that begins at the point
(6,6) and ends at the point (8. - 4).
a. Write a system of equations to model the problem.
b. Is it possible that the water skier could collide with the taxi? Explain
Mathematics
1 answer:
Eddi Din [679]3 years ago
8 0

I realize that the equation is different, but do it in the same way, it'll help! It is given that the water​ taxi's path can be modeled by the equation y =0.5(x - 14)^2. ​Therefore, this is one of the equations in this system. Find a linear equation that will model the path of the water​ skier, which begins at the point (6,6) and ends at the point (8,-4). The slope is (-5). Use the slope and one point on the line to find the​ y-intercept of the line.  The​ y-intercept of the line that passes through the points (6,6) and (8,-4) is (0,36). Thus, the equation is y=-5x+36. Now, to determine if it is possible for the water skier to collide with the​ taxi, we have to determine if there is a solution to the system of equations. To determine if there is a solution to the system of​ equations, solve the system using substitution.​ First, write the equation that models the water​ taxi's path in standard form. y=0.5(x - 14)^2-->0.5x^2-14x+98. Use substitution. Substitute for  y in the equation and then solve for  x. As the expression on the left side of the equation cannot easily be​ factored, use the Quadratic Formula to solve for x. Do x=-b(plusorminus)sqrrtb^2-4ac/2a. Identify a, b, and c. a=0.5, b=-9, and c=62. Substitute into the Quadratic Formula. If there is a negative number under the radical, there are NO solutions. Thus, the path of the water skier will never cross the path of the taxi.

In conclusion: It is not possible that the water skier could collide with the taxi as the two paths never cross.

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Answer:  X=17

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3 years ago
I’ve never been so confused, this is due in a few minutes, pls help if you can!
algol13

Given:

m(ar QT) = 220

m∠P = 54

To find:

The measure of arc RS.

Solution:

PQ and PT are secants intersect outside a circle.

<em>If two secants intersects outside a circle, then the measure of the angle formed is one-half the positive difference of the measures of the intercepted arcs.</em>

$\Rightarrow \angle P = \frac{1}{2} (m \ ar (QT) - m \ ar (RS ))

$\Rightarrow 54 = \frac{1}{2} (220- m \ ar (RS ))

Multiply by 2 on both sides.

$\Rightarrow 2 \times 54 = 2 \times  \frac{1}{2} (220- m \ ar (RS ))

$\Rightarrow 108= 220- m \ ar (RS )

Subtract 220 from both sides.

$\Rightarrow 108-220= 220- m \ ar (RS )-220

$\Rightarrow -112= -m \ ar (RS )

Multiply by (-1) on both sides.

$\Rightarrow (-112)\times(-1)= -m \ ar (RS )\times(-1)

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The measure of arc RS is 112.

6 0
3 years ago
Mei Su had 80 coins. She gave most of them to her friends in such a way that each of her friends got at least one coin and no tw
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Answer: 12 friends.

Step-by-step explanation:

the data we have is:

Mei Su had 80 coins.

She gave the coins to her friends, in such a way that every friend got a different number of coins, then we have that:

The maximum number of friends that could have coins is when:

friend 1 got 1 coin

friend 2 got 2 coins

friend 3 got 3 coins

friend N got N coins

in such a way that:

(1 + 2 + 3 + ... + N) ≥ 79

I use 79 because "she gave most of the coins", not all.

We want to find the maximum possible N.

Then let's calculate:

1 + 2 + 3 + 4 + 5 = 15

15 + 6 + 7 + 8 + 9 + 10 = 55

now we are close, lets add by one number:

55 + 11 = 66

66 + 12 = 78

now, we can not add more because we will have a number larger than 80.

Then we have N = 12

This means that the maximum number of friends is 12.

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The information is really hard to follow, you should ask the question with a screenshot of the data table.

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