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Anuta_ua [19.1K]
3 years ago
14

PLEASE HELP ASAP!!!!

Mathematics
2 answers:
nikdorinn [45]3 years ago
6 0

Answer:

Given: Data for 5 Days

Part A:-

No. of creatures on 6th day = Average/Mean of the Given Data

\text{Mean = }\frac{\text{Sum of all the observation}}{\text{Total No. of observation}}

⇒ \text{Mean = }\frac{42+26+61+65+56}{5}

⇒ Mean = 50

∴She collect 50 creatures on day 6.

Part B:-

As we Predicted she collected 50 pokenmon on day 6. So her Average is 50.

if She collected 53 creatures, then the average will be-

\text{Average = }\frac{42+26+61+65+56+53}{6}

⇒ Average = 50.5

Therefore, her new average become 50.5

Part C:-

There is no fixed no of creature collected on day 6,7,8. It can be increased or Decreased but her average will always be around 50.

musickatia [10]3 years ago
3 0
Let us model this problem with a polynomial function.

Let x =  day number (1,2,3,4, ...)
Let y = number of creatures colled on day x.

Because we have 5 data points, we shall use a 4th order polynomial of the form
y = a₁x⁴ + a₂x³ + a₃x² + a₄x + a₅

Substitute x=1,2, ..., 5 into y(x) to obtain the matrix equation
|   1     1    1    1    1  |  | a₁ |      | 42 |
| 2⁴  2³  2²  2¹  2⁰  |  | a₂ |      | 26 |
| 3⁴  3³  3²  3¹  3⁰   |  | a₃ |  =  | 61 |
| 4⁴  4³  4²  4¹  4⁰   |  | a₄ |      | 65 |
| 5⁴  5³  5²  5¹  5⁰  |  | a₅ |      | 56 |

When this matrix equation is solved in the calculator, we obtain
a₁ =      4.1667
a₂ =  -55.3333
a₃ =  253.3333
a₄ =  -451.1667
a₅ =   291.0000

Test the solution.
y(1) = 42  
y(2) = 26
y(3) = 61
y(4) = 65
y(5) = 56

The average for 5 days is (42+26+61+65+56)/5 = 50.
If Kathy collected 53 creatures instead of 56 on day 5, the average becomes
(42+26+61+65+53)/5 = 49.4.

Now predict values for days 5,7,8.
y(6) = 152
y(7) = 571
y(8) = 1631


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The <em>rigid</em> transformations used for each figure:

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<h3>What transformation rules do create the resulting images?</h3>

In this question we must determine what kind of <em>rigid</em> transformations generates each image. <em>Rigid</em> transformations are transformations applied on geometric loci such that <em>Euclidean</em> distance is conserved. Now we proceed to determine the transformation rule for each case:

Figure 5 - Reflection around the x-axis followed by reflection around the y-axis.

(x, y) → (- x, - y)

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(x, y) → (x + 1, y - 2)

To learn more on transformation rules: brainly.com/question/9201867

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nirvana33 [79]

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If you go to a website with a graph place the points and look where the line sets

Step-by-step explanation:

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3 years ago
PLZ PLZ HALP!!
bogdanovich [222]

Answer:

(A) - (5)

(B) - (4)

(C) - (1)

(D) - (2)

Step-by-step explanation:

(A) We are given the polynomial (x+4)(x−4)[x−(2−i)][x−(2+i)]

(5) The related polynomial equation has a total of four roots; two roots are complex and two roots are real.

(B) We are given the polynomial (x+i)(x−i)(x−2)³(x−4).

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(1) The related polynomial equation has a total of four roots; all four roots are real and one root has a multiplicity of 2.

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3 years ago
Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 7.8 parts
Alexxandr [17]

Answer:

The value of the test statistic is t = 2.67

Step-by-step explanation:

The null hypothesis is:

H_{0} = 7.8

The alternate hypotesis is:

H_{1} \neq 7.8

Our test statistic is:

t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

In this problem, we have that:

X = 8.2, \mu = 7.8, \sigma = 0.6, n = 16

Then

t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

t = \frac{8.2 - 7.8}{\frac{0.6}{\sqrt{16}}}

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