The distance from the center of dilation, P, to.the image vertice S' is; 6 units.
<h3>What is the distance from the center of dilation, P, to the image S'?</h3>
It follows from the task content that the center of dilation of the triangle QRS is point P and the length of segment PS in the pre-image is; 8 units.
Hence, since the dilation factor as given in the task content is; three-fourths, it therefore follows that the distance of point P to S' in the image is; (3/4) × 8 = 6units.
Read more on dilation;
brainly.com/question/10253650
#SPJ1
10C4 represent the Combinations of 10 objects taken 4 at a time.
The formula for nCr is:

In the given case, n=10 and r=4. Using these values we get:

This means we can make 210 combinations of 10 objects taken 4 at a time.
They all only have 1 term.
Let
x= total cost of cars
y= total commission paid out for all cars sold
6%= 6/100 = .06
Set up an equation:
y= .06(x)
Given: x= $125,650
substitute into the y= .06(x)
multiply $125,650 by .06.
The answers would be: 7539
hope this helped :)
6)x-7+10 7)3+x+1 8)8x-16 9)x/2-9