Answer:
The students can group themselves in 360360 ways
Step-by-step explanation:
For this exercise we need to use the following equation:
This equation give us the number of assignation of n elements in k cell, where n1, n2, ..nk are the element that are in every cell
In this case we have 15 student that need to be assign in three vehicles with an specific capacity. This vehicles would be the equivalent to cells, so we can write the equation as:
Because the first vehicle have 7 seating, the second vehicle have 5 seating and the third vehicle have 3 seating.
Solving the equation we get 360360 ways to organized 15 students in three vehicles with capacity of 7, 5 and 3 seating.
Answer:
8 one-dollar bills
3 five-dollar bills
2 ten-dollar bills
Step-by-step explanation:
Let x = # of one-dollar bills, y = # of five-dollar bills, and z = # of ten-dollar bills. Total amount in the wallet is $43, so the first equation would be 1x + 5y + 10z = 43. Next, there are 4 times as many one-dollar bills as ten-dollar bills, so x = 4z. There are 13 bills in total, so x + y + z = 13
x + 5y + 10z = 43
x = 4z
x + y + z = 13
x + 5y + 10z = 43
x + 0y - 4z = 0
x + y + z = 13
5y + 14z = 43
-y - 5z = -13
5y + 14z = 43
-5y - 25z = -65
-11z = -22
z = 2
x = 4z
x = 4*2 = 8
x + y + z = 13
8 + y + 2 = 13
10 + y = 13
y = 3
Answer:
5400
Step-by-step explanation:
6x900 =5400 this is the correct answer
There would be 1,320 different ways, just multiply all the possible front runners 12 second runners 11 and third runners 10, 12x11x10=1,320
The system of equation that can be used to represent the number of meals sold is
x + y = 1000
5x + 10y = 3,500
Given:
Number of $5 meals sold = x
Number of $10 meals sold = y
Total number of meals = 1000
Total amount of meals = $3,500
The equations:
Quantity
x + y = 1000
Price
5x + 10y = 3,500
Therefore, the system of equation that can be used to represent the number of meals sold is
x + y = 1000
x + y = 10005x + 10y = 3,500
Learn more about equation:
brainly.com/question/15165519
