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3 years ago

Fill in the blanks below in order to justify whether or not the mapping

Mathematics

1 answer:

KATRIN_1 [288]3 years ago

6 0

Answer:

The mapping diagram above is a function since there are no two values (integers) in the range (Set B) where there is only one value (integer) in the domain (Set A) mapped unto them

Step-by-step explanation:

By definition a function is an association between the individual elements within two sets such that all element in one set is mapped to precisely one element of the other set

In the given example, all the elements in Set A are mapped to exactly one element of the Set B

That is the function from A to B is the set C (-1, -4), (9, 5), (1, 4), whereby the first component of the ordered pair in the set C are the elements of the set A.

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2. XYZW is a parallelogram with diagonals XZ and YW that intersect at point A.

sergeinik [125]

Answer:

AW=10

Step-by-step explanation:

In a parallelogram opposite sides are congruent meaning XA and AZ are congruent. YA and AW are congruent. So...

Solving for XA and AZ

XA=AZ

3m=5m-4

-2m=-4

m=2

If YW=10m then 10 x 2 = 20

20 divided by 2 = 10

4 0

2 years ago

Please help me ASAP!!! could someone help me do my geometry?

elena-14-01-66 [18.8K]

Answer:

9. m(YZ) = 102°

10. m(JKL) = 192°

11. m<GHF = 75°

Step-by-step explanation:

9. First, find the value of x

4x + 3 = 3x + 15 (inscribed angle that are subtended by the same arc are equal based on the inscribed angle theorem)

Collect like terms

4x - 3x = -3 + 15

x = 12

4x + 3 = ½(m(YZ)) (inscribed angle of a circle = ½ the measure of the intercepted arc)

Plug in the value of x

4(12) + 3 = ½(m(YZ))

48 + 3 = ½(m(YZ))

51 = ½(m(YZ))

Multiply both sides by 2

51*2 = m(YZ)

102 = m(YZ)

m(YZ) = 102°

10. First, find the value of x.

7x + 5 + 6x + 6 = 180° (opposite angles in an inscribed quadrilateral are supplementary)

Add like terms

13x + 11 = 180

13x = 180 - 11

13x = 169

x = 169/13

x = 13

7x + 5 = ½(m(JKL)) (inscribed angle of a circle = ½ the measure of the intercepted arc)

Plug in the value of x

7(13) + 5 = ½(m(JKL))

96 = ½(m(JKL))

Multiply both sides by 2

2*96 = m(JKL)

m(JKL) = 192°

11. First, find x.

5x + 15 = ½(11x + 18) (inscribed angle of a circle = ½ the measure of the intercepted arc)

Multiply both sides by 2

2(5x + 15) = 11x + 18

10x + 30 = 11x + 18

Collect like terms

10x - 11x = -30 + 18

-x = -12

Divide both sides by -1

x = 12

m<GHF = 5x + 15

Plug in the value of x

m<GHF = 5(12) + 15

m<GHF = 60 + 15

m<GHF = 75°

4 0

2 years ago

Show with work please.

kolbaska11 [484]

Answer:

$\csc \left(\theta-\frac{\pi }{2}\right)=0.73$

Step-by-step explanation:

The identity you will use is:

$\csc \left(x\right)=\frac{1}{\sin \left(x\right)}$

So,

$\csc \left(\theta-\frac{\pi }{2}\right)$

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{\sin \left(-\frac{\pi }{2}+\theta\right)}$

Now, using the difference of sin

Note: state that $\text{sin}(\alpha\pm \beta)=\text{sin}(\alpha) \text{cos}(\beta) \pm \text{cos}(\alpha) \text{sin}(\beta)$

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{-\cos \left(\theta\right)\sin \left(\frac{\pi }{2}\right)+\cos \left(\frac{\pi }{2}\right)\sin \left(\theta\right)}$