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WARRIOR [948]
3 years ago
5

A stadium brings in 16.25 million per year. It pays football related expenses of 13.5 million and stadium expenses of 2.7 millio

n per year. What is the stadiums current profit? a) $0 b) $25,000 c) $50,000 d) $100,000
Mathematics
1 answer:
Alexxx [7]3 years ago
4 0

Answer:

Option C) $50,000

Step-by-step explanation:

We are given the following in the question:

Earning of stadium = 16.25 million per year.

Football expense = 13.5 million per year

Stadium expenses = 2.7 million per year

Profit earned by stadium =

Earning of stadium - Football expenses - Stadium expenses

=16.5-13.5-2.7\\=0.05\text{ millions }\\=0.05\times 10^6\\=50,000\text{ Dollars per year}

Thus, the correct answer is

Option C) $50,000

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MATH HELP!!! 100PTS!!!
Lostsunrise [7]

Answer:

x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}

Step-by-step explanation:

<u>Given functions</u>:

  p(x)=2x-4

  r(x)=\dfrac{6x-1}{9x+1}

Solve for p(x) = r(x):

\begin{aligned}p(x) & = r(x)\\\implies 2x-4 & = \dfrac{6x-1}{9x+1}\\(2x-4)(9x+1)&=6x-1\\18x^2+2x-36x-4&=6x-1\\18x^2-40x-3&=0\end{aligned}

As the found quadratic equation cannot be factored, use the Quadratic Formula to solve for x:

<u>Quadratic Formula</u>

x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0

Therefore:

a=18, \quad b=-40, \quad c=-3

Substitute the values of a, b and c into the <u>quadratic formula</u> and solve for x:

\begin{aligned}\implies x & =\dfrac{-(-40) \pm \sqrt{(-40)^2-4(18)(-3)} }{2(18)}\\\\& =\dfrac{40 \pm \sqrt{1816}}{36}\\\\& =\dfrac{40 \pm \sqrt{4 \cdot 454}}{36}\\\\& =\dfrac{40 \pm \sqrt{4}\sqrt{454}}{36}\\\\& =\dfrac{40 \pm2\sqrt{454}}{36}\\\\& =\dfrac{20 \pm\sqrt{454}}{18}\end{aligned}

Therefore, the solutions are:

x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}

Learn more about quadratic equations here:

brainly.com/question/27750885

brainly.com/question/27739892

6 0
2 years ago
Find the slope between these two points: (3, -10) and (-2, -30). Show all of your work. what the answer
Harlamova29_29 [7]

\huge\text{$m=\boxed{4}$}

Hey there! Start with the slope formula, where (x_1,y_1) and (x_2,y_2) are the two known points.

\begin{aligned}m&=\dfrac{y_2-y_1}{x_2-x_1}\\&=\frac{-30-(-10)}{-2-3}\end{aligned}

Simplify.

\begin{array}{c|l}\textbf{Solving}&\textbf{Reason}\\\cline{1-2}\\m=\dfrac{-30+10}{-2-3}&x-(-y)=x+y\\\\m=\dfrac{-20}{-5}&\text{Addition and subtraction}\\\\m=\dfrac{20}{5}&\text{The negatives cancel out}\\\\m=\dfrac{4}{1}&\text{Divide the numerator and denominator by $5$}\\\\m=\boxed{4}&\dfrac{x}{1}=x\end{aligned}

3 0
3 years ago
Read 2 more answers
How to write<br><br> half of a <br><br>as an expression ​
Flura [38]

Answer:

1/2

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
The "feasible region" has vertices (4,5), (4,6), (7,4), and (3,6). If the "objective function" that you are trying to minimize i
Tanzania [10]

Answer:

The minimum value is 24

Step-by-step explanation:

we know that

The "feasible region" has vertices (4,5), (4,6), (7,4),(3,6)

The objective function is C=4x+2y

To determine the minimum value of the objective function, substitute the value of x and the value of y of each vertex in the objective function and then compare the values

1) For (4,5)

x=4,y=5

C=4(4)+2(5)=26

2) For (4,6)

x=4,y=6

C=4(4)+2(6)=28

3) For (7,4)

x=7,y=4

C=4(7)+2(4)=36

4) For (3,6)

x=3,y=6

C=4(3)+2(6)=24

therefore

The minimum value is 24

7 0
3 years ago
Please solve this question and explain it and how to do it: What is the slope of the line 2 - y = 8x
Schach [20]

Answer:

The slope is : -8/1

Step-by-step explanation:

2-y=8x

We need to get “y” by itself , so subtract “ 2 “ from both sides

-y=8x-2

Then we still have to get “ y” by itself , but it’s Negative “y” now! Divide both sides by “ negative one “ (-y is just like -1y).

-y/-1 = 8x/-1 (-2/-1)  

* I put the -2/-1 on () just to organize it *

y = -8x +2

2: y-intercept

-8: slope

[ y = -8x + 2 ] and this called the y-intercept form .✨


4 0
3 years ago
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