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2 years ago

3. (a) Calculate the compound interest over an amount of N$ 58 000 that is invested for 6 years at a rate of 5% pa

Mathematics

1 answer:

seropon [69]2 years ago

3 0

Answer:

The final balance is $78,243.04.

The total compound interest is $20,243.04.

Step-by-step explanation:

Year Principal Yearly Interest Total Interest Total Balance

0 58,000 0 0 58,000

1 58,000 2,967.39 2,967.39 60,967.39

2 58,000 3,119.21 6,086.6 64,086.6

3 58,000 3,278.79 9,365.4 67,365.4

4 58,000 3,446.54 12,811.94 70,811.94

5 58,000 3,622.88 16,434.82 74,434.82

6 58,000 3,808.23 20,243.04 78,243.04

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Step-by-step explanation:

We can calculate this confidence interval using the population proportion calculation. To do this we must find p' and q'

Where p' = 14/100= 0.14 (no of left handed sample promotion)

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Since the requested confidence level is CL = 0.98, then α = 1 – CL = 1 – 0.98 = 0.02/2= 0.01, z (0.01) = 2.326

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2 years ago

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We use Taylor series expansion to answer this question.

We have to find the expansion of cos x at x = 0

f(x) = cos x, f'(x) = -sin x, f''(x) = -cos x, f'''(x) = sin x, f''''(x) = cos x

Now we evaluate them at x = 0.

f(0) = 1, f'(0) = 0, f''(0) = -1, f'''(0) = 0, f''''(0) = 1

Now, by Taylor series expansion we have

f(x) = f(a) + f'(a)(x-a) + $\frac{f''(a)(x-a)^2}{2!}$ + $\frac{f'''(a)(x-a)^3}{3!}$ + $\frac{f''''(a)(x-a)^4}{4!}$ + ...

Putting a = 0 and all the values from above in the expansion, we get,

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2 years ago

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Ksenya-84 [330]

Answer:

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Step-by-step explanation:

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using the above properties, we can deduce the results as:

logₓ(y) = n is equivalent to y = xⁿ

therefore,

the given equation can be deduced as:

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into,

x = 6¹

x = 6

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2 years ago

3. (a) Calculate the compound interest over an amount of N$ 58 000 that is invested for 6 years at a rate of 5% pa​

3. (a) Calculate the compound interest over an amount of N$ 58 000 that is invested for 6 years at a rate of 5% pa