Rewrite the given quadratic equation in standard form: Kx 2 + 2x - 1 = 0
Discriminant = 4 - 4(K)(-1) = 4 + 4K
For the equation to have two real solutions, the discriminant has to be positive. Hence we need to solve the inequality 4 + 4K > 0.
The solution set to the above inequality is given by: K > -1 for which the given equation has two real solutions.
Answer:
These types of questions are not daunting if you break it down. First look at "Five less than twice the value of a number."
"Twice the value of a number" is simply 2x.
"Five less" is simply -5, so for the first part we have (2x-5)
Next, analyze the second part. "Three times the quantity of four more than one half the number."
Looking at "Three times the quantity" simply means "3 times something".
"the quantity of four more than one half the number" is 4 + "one half the number" or 4 + (1/2)x.
So the second part is simply 3(4+x/2).
Finally we finish the entire equation, (2x-5) = 3(4+x/2) then solve for x.
2x-5 = 12 + (3/2)x
2x-(3/2)x = 17
x/2 = 17
x=34
Checking the left side, (2x-5) = 2(34) - 5 = 63.
Checking the right side, 3(4+(34/2)) = 3(4+17) = 3(21) = 63.
Answer:
f(2) =4, f(4) =4, x=8, x=3
Step-by-step explanation:
f(2) is asking for what the y value is when x is 2. f(4) is also asking what the y value is when x=4. When y=-2 the x is 8 and when the y=6 x=4. I hope this is helpful.
So using standard form you convert the equation to 5x - 2y = -10 then use slope m of a line of the form Ax + By = C equals negative a over b. It would be a = 5 b = -2 m = -5/-2 m = 5/2. Have a good day the answer is 5/2
