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xenn [34]
3 years ago
8

What are the slope and why intercept shown on the graph below

Mathematics
2 answers:
vfiekz [6]3 years ago
4 0
Hi there! The formula for finding the slope is y2 - y1/ x2 - x1, where the first x and y-coordinates are subtracted from the second x and y-coordinates. We have the two points on the graph marked. We will use (0, 5) and (4, -5) in this case. Here are the numbers that represent each:

y2 = -5
y1 = 5
x2 = 4
x1 = 0

Let's subtract. -5 - 5 is -10. 4 - 0 is 4. -10/4 is -2 1/2 in simplest form or -5/2 as a mixed number. We found the slope. The y-intercept is where the line crosses, where the x-axis is 0. In this case, we can see by the point given out that the slope intercept is 5. There. The slope is -5/2 and the slope-intercept is 5. The answer is B.
viktelen [127]3 years ago
3 0
Hello!

Let's start by finding the slope of the line. You can calculate the slope by dividing the change in y-values by the change in x-values using the following formula:

\frac{ y_{1}- y_{2}  }{ x_{1} - x_{2} }

The plotted coordinates are (0, 5) and (4, -5); let's plug those into the formula:

\frac{5(-5)}{0-4}

Simplify:

\frac{5+5}{-4}

\frac{10}{-4}

\frac{-5}{2}

The slope is \frac{-5}{2}.

Now, the y-intercept is where the line intersects the y-axis, or when x equals 0. x equals 0 when y equals 5, so the y-intercept is 5.

I hope this helps!
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Answer:

a0 = 10

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a0 + -7 = 3

a0 + -7 + 7 = 3 + 7

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Cheers.

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4. Identify the zeros and the graph of the function y = x(x − 2)(x + 5).
Natalka [10]

The zeros of

y = x(x + 2)(x + 5)y=x(x+2)(x+5)

are

x=0,x=-2,x=-5x=0,x=−2,x=−5

EXPLANATION

The given function is

y = x(x + 2)(x + 5)y=x(x+2)(x+5)

To find the zeros of the above function, we just have to equate the function to zero and solve for x.

x(x + 2)(x + 5) = 0x(x+2)(x+5)=0

This implies that,

x = 0 \: \: or \: x + 2 = 0 \:or \: x + 5 = 0x=0orx+2=0orx+5=0

x = 0 \: \: or \: x = - 2\:or \: x = - 5x=0orx=−2orx=−5

To graph the above function, we need to consider the multiplicity.

We can see that the multiplicity of the roots are odd. This means that, the graph crosses the x-axis at each x-intercept.

We also need to consider the position of the graph on the following intervals,

x < - 5x<−5

When

x = - 10x=−10

y = - 10( - 8)( - 5) \: < \: 0y=−10(−8)(−5)<0

The graph is below the x-axis.

- 5 \: < \: x \: < \: - 2−5<x<−2

When

x = - 3x=−3

y = - 3(2)( - 1) \: > 0y=−3(2)(−1)>0

The graph is above the x-axis.

- 2 \: < \: x < \: 0−2<x<0

when

x = - 1x=−1

y = -1(1)(4) \: < \: 0y=−1(1)(4)<0

The graph is below the x-axis.

Finally the interval,

x \: > \: 0x>0

when

x = 1x=1

y = 1(3)(6) \: > \: 0y=1(3)(6)>0

The graph is above the x-axis.

We can now use the above information to sketch graph as shown in the diagram above

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Select the graph of the solution set that would represent the following expression. (x-2)=5(x+1)​
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Answer:

Find the attached

Step-by-step explanation:

We have been given the following expression;

(x-2)=5(x+1)

We are required to determine the graph of the solution set. To do this we formulate the following set of equations;

y = x - 2

y = 5(x+1)

We then graph these two equations on the same cartesian plane. The solution will be the point where these two graphs intersect.

Find the attachment below;

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