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1 year ago

The base of a triangle is fixed at 2.218 millimeters. Determine the number of

Mathematics

1 answer:

harina [27]1 year ago

4 0

When the base of a triangle is fixed at 2.218 millimeters, the area will be 0.1098 mm².

It should be noted that the area of a triangle is calculated as:

Area of triangle = (1/2)×base×height

= (1/2) × 2.218 mm × 0.099 mm

= 1.109 mm × 0.099 mm

= 0.109791 mm²

≈ 0.1098 mm²

Therefore, the <em>area</em> is 0.1098 mm².

Learn more about triangles on;

brainly.com/question/2644832

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The base of a triangle is fixed at 2.218 millimeters. Determine the number of

significant figures of the area of the triangle with each given height of 0.099mm.

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I need help working question 8. I don't understand how to start it

Lina20 [59]

Why don't you first try to use the cosine law to solve for an angle and then make use of the sin law to solve for the remaining angles.

Cosine law

C^2 = A^2 + B^2 - 2AB(cos C)
Solve for cos C, and then take the inverse of the trig ratio to solve for the angle.

Then set up a proportion like you have done using the sin law and solve for another angle. Knowing the sum of all angles in a triangle add up to 180 degrees, we can easily solve for the remaining angle.

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3 years ago

A red balloon starts at 7.3 meters off the ground and rises at 2.6 meters per second. A blue balloon starts at 12.4 meters off t

nexus9112 [7]

This problem is an example of solving equations with variables on both sides. To solve, we must first set up an equation for both the red balloon and the blue balloon.

Since the red balloon rises at 2.6 meters per second, we can represent this part of the equation as 2.6s. The balloon is already 7.3 meters off of the ground, so we just add the 7.3 to the 2.6s:

2.6s + 7.3

Since the blue balloon rises at 1.5 meters per second, we can represent this part of the equation as 1.5s. The balloon is already 12.4 meters off of the ground, so we just add the 12.4 to the 1.5:

1.5s + 12.4

To determine when both balloons are at the same height, we set the two equations equal to each other:

2.6s + 7.3 = 1.5s + 12.4

Then, we solve for s. First, the variables must be on the same side of the equation. We can do this by subtracting 1.5s from both sides of the equation:

1.1s + 7.3 = 12.4

Next, we must get s by itself. We work towards this by subtracting 7.3 from both sides of the equation:

1.1s = 5.1

Last, we divide both sides by 1.1. So s = 4.63.

This means that it will take 4.63 seconds for both balloons to reach the same height. If we want to know what height that is, we simply plug the 4.63 back into each equation:

2.6s + 7.3
= 2.6 (4.63) + 7.3
= 19.33

1.5s + 12.4
= 1.5 (4.63) + 12.4
= 19.33

After 4.63 seconds, the balloons will have reached the same height: 19.33 meters.

6 0

3 years ago

Determine if the equation below is a function with independent variable x. If so, find the domain. If not, find a value of x to

Andre45 [30]

Answer:

No because it contains points (3,4) and (3,-4). You cannot have a x assigned to more than one y-value if you want it to be a function.

Step-by-step explanation:

A function has one output per input.

If we are trying to determine if the given is a function of x, then x is the input.

However I can get two outputs from plugging in x=3.

$3^2+y^2=25$

$9+y^2=25$

Subtract 9 on both sides:

$y^2=25-9$

$y^2=16$

Take the square root of both sides:

$y=\pm \sqrt{16}$

$y=\pm 4$ .

So input x=3 yields y=4 and y=-4.

Since this input has more than one output then the given is not a function of x.

----Also!

If you graph the equation, it is a circle with radius 5 and center (0,0). So I could I plug in any number for x between -5 and 5 excluding -5 and 5 which would yield only one output each. Since plugging in either one gives:

$(\pm 5)^2+y^2=25$