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Kryger [21]
3 years ago
11

I NEED HELP REALLY FAST!!!

Mathematics
1 answer:
nadya68 [22]3 years ago
3 0
Explain the question?
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Assume every 10-digit natural number is a possible telephone number except those that begin with 0, 1 or 2. What fraction of tel
lana [24]

Answer: 1/70

Step-by-step explanation:

This is a question that can also be interpreted as what is the probability of having the first number of a phone number to be 8 and the last number of the phone number to also be 8. This answer gives the fraction of the phone numbers that starts with 8 and end with 8.

Since three numbers (0,1,2) cannot start a phone number and we are left to pick from 7 numbers,

then the probability of figure "8" starting phone number = 1/7

Since all 10 numbers can possibly end a phone number,

then the probability of having figure "8" as the last digit of a phone number = 1/10

Hence probability of having "8" as the first and last digit of a phone number = fraction of total telephone numbers that begin with digit 8 and end with digit 8 = 1/7 × 1/10 = 1/70.

5 0
3 years ago
Use the standard norml distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justif
dalvyx [7]

Answer:

E) we will use t- distribution because is un-known,n<30

the confidence interval is (0.0338,0.0392)

Step-by-step explanation:

<u>Step:-1</u>

Given sample size is n = 23<30 mortgage institutions

The mean interest rate 'x' = 0.0365

The standard deviation 'S' = 0.0046

the degree of freedom = n-1 = 23-1=22

99% of confidence intervals t_{0.01} =2.82  (from tabulated value).

The mean value = 0.0365

x±t_{0.01} \frac{S}{\sqrt{n-1} }

0.0365±2.82 \frac{0.0046}{\sqrt{23-1} }

0.0365±2.82 \frac{0.0046}{\sqrt{22} }

0.0365±2.82 \frac{0.0046}{4.690 }

using calculator

0.0365±0.00276

Confidence interval is

(0.0365-0.00276,0.0365+0.00276)

(0.0338,0.0392)

the mean value is lies between in this confidence interval

(0.0338,0.0392).

<u>Answer:-</u>

<u>using t- distribution because is unknown,n<30,and the interest rates are not normally distributed.</u>

4 0
3 years ago
Please help me with this and I need the work shown out please
givi [52]
Please note that you have to use the reason vert. opp. angles to find x, hope it helps:)

5 0
3 years ago
What is the probability of getting the same number of heads and tails?<br>1/8<br>1/4<br>3/8<br>3/4
victus00 [196]
The probability of getting the same number of heads and tails is3/8
4 0
4 years ago
Please help me I don’t understand and my tutor is gonna tell me mom please help number 12
dem82 [27]

Answer:

20

Step-by-step explanation:

I assume y is 4/3 of z.

x = 7/6 y

y = 48

x = 7/6 * 48

x = 7 * 8

x = 56

y = 4/3 z

4/3 z = y

z = 3/4 y

z = 3/4 * 48

z = 36

x - z = 56 - 36 = 20

8 0
3 years ago
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