Answer:
f(x) = x² - 81 = ( x+ 9)(x - 9) Difference of two squares
g(x) = x+9/x-9
g(x) . f(x) = x + 9/ x - 9 × (x+9)(x - 9)
= ( x + 9)(x +9)
= ( x + 9)²
= x² + 18x + 81
Hope this helps.
When a wire is bent to form a circle then its length represents the circumference of the circle formed. Therefore in our case the circumference of the circle is 50 cm. we can use this to determine the radius of the circle and then determine the area. Circumference of a circle is given by \pi × diameter, (\pi = 3.142)
thus diameter will be given by 50 cm ÷ 3.142 = 15.9134 cm
the radius will be 15.9134 ÷2 = 7.9567 cm or ≈ 7.96 cm
The area of a circle is given by \pi × square of radius
Area = 3.142 × 7.96×7.96 = 199.0821 square cm
Thus the area of the circle formed is ≈ 199.08 square cm ( 2 decimal places)
DIY. I believe in you, its just a matter if you believe in yourself. Your welcome
Answer:
x<6/5, x>14/5
Step-by-step explanation:
Steps
$5\left|x-2\right|+4>8$
$\mathrm{Subtract\:}4\mathrm{\:from\:both\:sides}$
$5\left|x-2\right|+4-4>8-4$
$\mathrm{Simplify}$
$5\left|x-2\right|>4$
$\mathrm{Divide\:both\:sides\:by\:}5$
$\frac{5\left|x-2\right|}{5}>\frac{4}{5}$
$\mathrm{Simplify}$
$\left|x-2\right|>\frac{4}{5}$
$\mathrm{Apply\:absolute\:rule}:\quad\mathrm{If}\:|u|\:>\:a,\:a>0\:\mathrm{then}\:u\:<\:-a\:\quad\mathrm{or}\quad\:u\:>\:a$
$x-2<-\frac{4}{5}\quad\mathrm{or}\quad\:x-2>\frac{4}{5}$
Show Steps
$x-2<-\frac{4}{5}\quad:\quad x<\frac{6}{5}$
Show Steps
$x-2>\frac{4}{5}\quad:\quad x>\frac{14}{5}$
$\mathrm{Combine\:the\:intervals}$
$x<\frac{6}{5}\quad\mathrm{or}\quad\:x>\frac{14}{5}$
