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serious [3.7K]
3 years ago
11

What if f(5) if f(1) = 3.2 and f(x+1) = 5/2 (f(x))

Mathematics
1 answer:
dusya [7]3 years ago
4 0

Answer:

f(5)=125

Step-by-step explanation:

If f(1)=3.2 and f(x+1)=\dfrac{5}{2}f(x), then

  1. at x=1 you have f(2)=\dfrac{5}{2}\cdot f(1)=2.5\cdot 3.2=8;
  2. at x=2 you have f(3)=\dfrac{5}{2}\cdot f(2)=2.5\cdot 8=20;
  3. at x=3 you have f(4)=\dfrac{5}{2}\cdot f(3)=2.5\cdot 20=50;
  4. at x=4 you have f(5)=\dfrac{5}{2}\cdot f(4)=2.5\cdot 50=125.
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Step-by-step explanation:

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Question down below. Answer for points
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Explain the error in the solution below. What additional step needs to be completed?
Dmitriy789 [7]

Answer:

From step 4 to 9 is the required steps shown below.

Step-by-step explanation:

Given : Solution below,

\log x -\log_5 3 = 2\log_5 3\\\log x = 3\log_5 3\\\log x = \log_5 33\\x = 27      

To find : The error in the solution and what additional step needs to be completed?

Solution : The mistake is the step 3 and additional step need to be added after it.

Step 1 - \log x -\log_5 3 = 2\log_5 3

Step 2 - \log x = 3\log_5 3

Step 3 - \log x =\log_5 3^3

Step 4 - \log x=\log_5 27

Applying change base rule of logarithmic, \log_b a=\frac{\log a}{\log b}

Step 5 - \log x=\frac{\log 27}{\log 5}

Step 6 - \log x=\frac{1.431}{0.698}

Step 7 - \log x=2.050

Step 8 - x=10^{2.050}

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From step 4 to 9 is the required steps.

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. How many strings are there of lowercase letters of length four or less, not counting the empty string
lesantik [10]
<h3>Answer:  475,254</h3>

This is one single number and not two separate numbers.

Delete the comma if your teacher requires it.

=========================================================

Explanation:

I'm assuming letters can repeat.

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There are,

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Overall, there are A+B+C+D = 456,976+17,576+676+26 = 475,254 strings of length four or less.

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a stone is dropped in a river from a bridge . if it takes 4 seconds to reach of the surface of water, calculate the depth of the
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The stone takes 4sec to reach the water level.

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