Given:
Line segment NY has endpoints N(-11, 5) and Y(3,-3).
To find:
The equation of the perpendicular bisector of NY.
Solution:
Midpoint point of NY is




Slope of lines NY is




Product of slopes of two perpendicular lines is -1. So,


The perpendicular bisector of NY passes through (-4,1) with slope
. So, the equation of perpendicular bisector of NY is




Add 1 on both sides.

Therefore, the equation of perpendicular bisector of NY is
.
12Answer:
Step-by-step explanation:
Answer: Step-by-step explanation: We are given an exponential equation.We need to convert it into it's equivalent equation.Let us factor 4.4 = 2 × 2Therefore, 2 × 2 could be written as .Now, let us factor 64 in terms of 2's.64 = 2 × 2× 2× 2× 2× 2 = .Replacing 4 by and 64 by in original equation, we get Distributing 2 over (x+3), we get
Answer:
A i think
Step-by-step explanation: