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Vlad1618 [11]
2 years ago
13

The standard form of 6050000 is given by​

Mathematics
1 answer:
tiny-mole [99]2 years ago
7 0

Answer:

6.05 * 10^6.

Step-by-step explanation:

There are 6 digits after the first digit 6,  so it's:

6.05 * 10^6

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Use the model to represent 80% as a fraction in simplest form.
statuscvo [17]

Answer: 45.

Step-by-step explanation:

5 0
2 years ago
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What is the range of the function y=-x² +1?<br> A) y≤ -1<br> B) y²-1<br> C) y≤ 1<br> D) y≥ 1
MakcuM [25]

Answer:

Option (C)

Step-by-step explanation:

The minimum value of x² is 0, and the maximum value is unbounded, so therefore, the maximum value of -x² is 0, and the minimum value is unbounded.

So, this means that adding 1 to this, the range matches with option C.

8 0
2 years ago
A segment in the coordinate plane has an endpoint with coordinates (1,2) and midpoint with coordinates (4,3). What are the coord
Serga [27]

Answer:

(7,4)

Step-by-step explanation:

midpoint formula (x1+x2)/2 , (y1+y2)/2

Look at x and y for the endpoints separately

midpoint x value = ( 1 + x)/2

4= (1 + x)/2

8 = 1 + x

x = 7

midpoint y value =  (2 + y)/2

3 = (2 + y)/2

6 = 2 + y

y = 4

endpoint (x,y) = (7,4)

8 0
3 years ago
The digits 4 comma 5 comma 6 comma 7 comma and 8 are randomly arranged to form a​ three-digit number. ​ (Digits are not​ repeate
fenix001 [56]

Answer:

0.1 or 1/10

Step-by-step explanation:

The digits 4, 5, 6, 7 and 8 are randomly arranged to form a three digit number, where the digits are not repeated.

This is question of permutation.

Imagine this sum as; there are 3 boxes(blank spaces for digits) and 5 different fruits(digits) are to be put in these boxes, where a box can hold a maximum of only 1 fruit. The number of such permutations are: ⁵P₃

By formula (a! is factorial a):

ᵃPₙ = \frac{a!}{(a-n)!}

⁵P₃ = \frac{5!}{(5-3)!}

⁵P₃ = \frac{5!}{2!}

⁵P₃ = \frac{5*4*3*2*1}{2*1}

⁵P₃= 60

This is the total count of possible numbers that can be formed.

Now, for a number to be greater than 800 and even; first digit should necessarily be 8. Last digit can be 4 or 6. Using these conditions, there are 6 possibilities. 854, 864, 874, 846, 856, 876 are the numbers.

The probability that number is even and greater than 800 is:

P=\frac{ favorable outcomes}{equally likely possible outcomes}

P=\frac{6}{60}

P=\frac{1}{10}

3 0
3 years ago
Hey, I would love it it someone could please answer this as soon as possible!
Ann [662]

Answer:


Step-by-step explanation:

x= -1/4

3 0
3 years ago
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