Ask question

Ask question

All categories

2 years ago

12

What is the domain of the function represented by the following graph?

1 answer:

Svetllana [295]2 years ago

6 0

Hello!

The domain of the function are the x-values that make the function true.

Since the graph has open circles and filled in circles, the open circles make the function false (written as <) , and the filled in circles make it true (written as ≤).

From the graph, the x value -3, and 2 are open circles. While the value -0.5 are filled in circles. Also, from the interval (-0.5, 2), there is gap, so it is part of the domain.

Therefore, the domain of the function is: {x | -3 < x ≤ -0.5} ∪ {x | 2 < x < ∞}, which is the third choice.

You might be interested in

The sum of 2/3m and 1/5

riadik2000 [5.3K]

13/15

Hope this helps

7 0

3 years ago

According to government data, 75% of employed women have never been married. Rounding to 4 decimal places, if 15 employed women

blagie [28]

Answer:

We are given that According to government data, 75% of employed women have never been married.

So, Probability of success = 0.75

So, Probability of failure = 1-0.75 = 0.25

If 15 employed women are randomly selected:

a. What is the probability that exactly 2 of them have never been married?

We will use binomial

Formula : $P(X=r) =^nC_r p^r q^{n-r}$

At x = 2

$P(X=r) =^{15}C_2 (0.75)^2 (0.25^{15-2}$

$P(X=2) =\frac{15!}{2!(15-2)!} (0.75)^2 (0.25^{13}$

$P(X=2) =8.8009 \times 10^{-7}$

b. That at most 2 of them have never been married?

At most two means at x = 0 ,1 , 2

So, $P(X=r) =^{15}C_0 (0.75)^0 (0.25^{15-0}+^{15}C_1 (0.75)^1 (0.25^{15-1}+^{15}C_2 (0.75)^2 (0.25^{15-2}$

$P(X=r) =(0.75)^0 (0.25^{15-0}+15 (0.75)^1 (0.25^{15-1}+\frac{15!}{2!(15-2)!} (0.75)^2 (0.25^{15-2})$

$P(X=r) =9.9439 \times 10^{-6}$

c. That at least 13 of them have been married?

P(x=13)+P(x=14)+P(x=15)

$={15}C_{13}(0.75)^{13} (0.25^{15-13})+{15}C_{14} (0.75)^{14}(0.25^{15-14}+{15}C_{15} (0.75)^{15} (0.25^{15-15})$

$=\frac{15!}{13!(15-13)!}(0.75)^{13} (0.25^{15-13})+\frac{15!}{14!(15-14)!} (0.75)^{14}(0.25^{15-14}+{15}C_{15} (0.75)^{15} (0.25^{15-15})$

$=0.2360$

8 0

3 years ago

Jon is making hamburgers for a church lunch. He has 42 2/3 lbs of ground beef . How many 1/3 pound hamburgers can he make using

Tatiana [17]

128 pounds of ground beef

4 0

3 years ago

I really need help! :'(<br><br> Domain= ?<br><br> Range= ?

hodyreva [135]

Domain = {x|x = 2, 9, 6}
Range = {y|y = c, 0}

I think this is the answer? I tried, it's better to fill it in than to leave it blank :/

7 0

3 years ago

What is the value of y in the equation 2(3y - 4) = 10 ?<br><br> Question 1 options:<br><br> 1

Andrews [41]

Y is y=3 so the awnser is y=3

3 0

3 years ago

Read 2 more answers