This would be ELA 1 or 2.....
Answer:
Answer of 17 is ㏒(
+15x), Answer of 33 is x = 8 , Answer of 35 is x = ㏒10/㏒2 , Answer of 37 is x = -㏒12/㏒8 and Answer of 39 is x = 5
Step-by-step explanation:
17. ㏒x + ㏒(x+15)
Using property ㏒a + ㏒b = ㏒a×b
∴ ㏒x + ㏒(x+15)
㏒x×(x+15)
㏒(
+15x)
The answer is ㏒(
+15x)
33. 2^(x-5) = 8
2^(x-5) = 2^3
Using property 2^a = 2^b
Then a = b
∴x-5 = 3
x = 8
The answer is x = 8
35. 2^x = 10
Taking log on both sides gives
㏒2^x = ㏒10
x×㏒2 = ㏒10
x = ㏒10/㏒2
The answer is x = ㏒10/㏒2
37. 8^-x = 12
Taking log on both sides gives
㏒8^-x = ㏒12
-x×㏒8 = ㏒12
x = -㏒12/㏒8
The answer is x = -㏒12/㏒8
39. 5(2^3 × x) = 8
5(8×x) = 8
x = 5
The answer is x=5
Answer:
Each of them will get 3.375 inches of cookie.
Step-by-step explanation:
Rasputen and his three buddies are splitting a giant 18 inches cookie.
But they notice that
th of it is missing.
So, the actual length of the cookie is
inches.
If all the four of them get the same amount of the giant cookie then each of them will get
inches of cookie. (Answer)
Answer:
B
Step-by-step explanation:
n³-125=0
n³=125
n= ³√125
n=5
Nitrogen Radius = 5.8 x 10⁻¹¹ m
Beryllium Radius = 1.12 x 10⁻¹⁰ m
Let's find the quotient of N/Be :
(5.8x10⁻¹¹)/(1.12x10⁻¹⁰). But 10⁻¹¹/10⁻¹⁰ = 10⁽⁻¹¹⁺¹⁰⁾ = 10⁻¹ = 1/10 = 0.1
→ (5.8/1.12).(0.1) = 0.58/1.12 = 0.518.
Conclusion: the radius of Be is almost double than the radius of N