Answer:
4
Step-by-step explanation:
Where on the X-axis do they intersect? 4
Answer:
2:5
Step-by-step explanation:
david=24mins
mark = 1hour
change 1 hour to mins
DAVID=24
MARK=60
24:60
THEN SIMPLIFY
24/60
<em>=</em><em>2</em><em>/</em><em>5</em>
<em><u>2</u></em><em><u>:</u></em><em><u>5</u></em>
Add the exponents and keep the same base. Then reciprocal it and change the sign of the exponent. Then the value of the exponent expression is 0.5.
<h3>What is an exponent?</h3>
Exponential notation is the form of mathematical shorthand which allows us to write complicated expressions more succinctly. An exponent is a number or letter is called the base. It indicates that the base is to raise to a certain power. X is the base and n is the power.
The exponent expression is 2³ × 2⁻⁴ can be simplified.
Add the exponents and keep the same base. Then we have
2³ × 2⁻⁴ = 2⁽³⁻⁴⁾
2³ × 2⁻⁴ = 2⁻¹
Then find the reciprocal and change the sign of the exponent.

The value is 0.5.
More about the exponent link is given below.
brainly.com/question/5497425
Answer:
A. h(x)= -5.86x^2 + 23.37x + 34
Step-by-step explanation:
If the scientist uses the same amount of pesticide on the two farms then the x's of the functions are the same.
Then, the combined yield
of the two farms is just the yield of the first farm plus the yield of the second farm:
.
Now, since

and
,
then

we add the coefficients of the corresponding terms to get:


Which is choice A.
Answer: function 1
Rate of change of function 1:
Following the format of y=mx+c, the rate of change should be m, so, the rate of change for function 1 = 4
To find the gradient (rate of change):
The two points the line passes through are (x1, y1) and (x2, y2), which in this case is (1, 6) and (3, 10)
(Doesn't matter which is which but you need to make sure that once you decide which is which, you stick to it)
To calculate the gradient, you substitute these values following (y1 - y2)/(x1 - x2)
Gradient of function 2 = (10 - 6)/(3 - 1)
= 2
Therefore, since 4 > 2, rate of change of function 1 > rate of change of function 2.