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olga55 [171]
3 years ago
13

8) What value of x will make the equation below true?x−4.3=2.8

Mathematics
1 answer:
Jlenok [28]3 years ago
7 0
7.1
X - 4.3 = 2.8
Add 4.3 to both sides
X = 7.1
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A candy bar box is in the shape of a triangular prism the volume of the box is 2400 cubic centimeters part A: what is the height
Whitepunk [10]
The volume of a triangular prism is the "area of a triangle" times the "thickness."
The area of a triangle is (base times height) over 2.
V = ((b*h)/2)*T
Given V = 2400 cu. cm, b = 16 cm, T = 20 cm, and h is unknown,
h = (2V)/(bL) = (2*2400)/(16*20) = 15 cm

Note that the given 17 cm in the picture is useless.
3 0
4 years ago
I AM BEGGING YALL TO HELP ME BRAINLYEST
Harrizon [31]

Answer:

56

Step-by-step explanation:

PEMDAS

4+372-320

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3 0
3 years ago
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Find sinϴ and cosϴ if tanϴ=1/4 and sinϴ>0
eduard
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2787701

_______________


\mathsf{tan\,\theta=\dfrac{1}{4}\qquad\qquad(sin\,\theta\ \textgreater \ 0)}\\\\\\
\mathsf{\dfrac{sin\,\theta}{cos\,\theta}=\dfrac{1}{4}}\\\\\\
\mathsf{4\,sin\,\theta=cos\,\theta\qquad\quad(i)}


Square both sides:

\mathsf{(4\,sin\,\theta)^2=(cos\,\theta)^2}\\\\
\mathsf{4^2\,sin^2\,\theta=cos^2\,\theta}\\\\
\mathsf{16\,sin^2\,\theta=cos^2\,\theta\qquad\qquad(but,~cos^2\,\theta=1-sin^2\,\theta)}\\\\
\mathsf{16\,sin^2\,\theta=1-sin^2\,\theta}

\mathsf{16\,sin^2\,\theta+sin^2\,\theta=1}\\\\
\mathsf{17\,sin^2\,\theta=1}\\\\
\mathsf{sin^2\,\theta=\dfrac{1}{17}}\\\\\\
\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{1}{17}}}\\\\\\
\mathsf{sin\,\theta=\pm\,\dfrac{1}{\sqrt{17}}}


Since \mathsf{sin\,\theta} is positive, you can discard the negative sign. So,

\mathsf{sin\,\theta=\dfrac{1}{\sqrt{17}}\qquad\quad\checkmark}


Substitute this value back into \mathsf{(i)} to find \mathsf{cos\,\theta:}

\mathsf{4\cdot \dfrac{1}{\sqrt{17}}=cos\,\theta}\\\\\\
\mathsf{cos\,\theta=\dfrac{4}{\sqrt{17}}\qquad\quad\checkmark}


I hope this helps. =)


Tags:   <em>trigonometric identity relation trig sine cosine tangent sin cos tan trigonometry precalculus</em>

7 0
3 years ago
How to solve 37=-3+5(x+6)
zavuch27 [327]
Distribute Property 5(x+6) basically means 5×x + 5×6 = 5x+30

37= -3+5x+30 (subtract 30 on both sides)

7=-3+5x (add three on both sides)

10= 5x (divide 5 on both sides)

x=2 
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3 years ago
U=kvw/x for x<br> how do you solve this?
ratelena [41]

Answer:

idk like f.r.

Step-by-step explanation:

n / 1a

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