A
a) y+6x=5 if x= -1 then y+6(-1)=5 then y = 11
b) same thing if x = 3 then y+6(3)=5 y+18=5 subtract both sides by -18 and leave y on left then add 5+(-18)= 13 then y=13
B same as above
question (a) asks you to solve for y because x is -2
(b) asks you to solve for x because y is known
3x+2y=-6 if y = 3 you write 3x+2(3)=-6 3x+6=-6 move the +6 over to right side by subtracting 6 from both side 3x=-6 + -6 so 3x=-12 to get rid of the 3 and only leave the x you want to divide both side by 3 then x= -12/3 then the answer would be x=-4
Answer:
well what is the question here?
Step-by-step explanation:
Answer:
6000 square millimeters
Step-by-step explanation:
Side length of the slanting side can be calculated using the Pythagorean theorem,
L = sqrt(30^2+40^2) = 50
sufrace area of a triangular prism
= surface area of the end sections + the surface area of the three side faces
= 2*(30*40/2) + 40*(30+40+50)
= 1200 + 4800
= 6000 mm^2
Answer:
The train need to leave Portland at 03:27 am
Step-by-step explanation:
step 1
Find out how long it takes the train to travel from Portland, Oregon, to Los Angeles, California
Remember that
The speed is equal to divide the distance by the time
so
The time is equal to divide the distance by the speed
Let
s ---> the speed in miles per hour
d ---> the distance in miles
t ---> the time in hours
![t=\frac{d}{s}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7Bd%7D%7Bs%7D)
we have
![d=963\ mi](https://tex.z-dn.net/?f=d%3D963%5C%20mi)
![s=60\ mi/h](https://tex.z-dn.net/?f=s%3D60%5C%20mi%2Fh)
substitute
![t=\frac{963}{60}=16.05\ hours](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B963%7D%7B60%7D%3D16.05%5C%20hours)
step 2
Adds 30 minutes (time it takes to get from the train station to her aunt's house)
Remember that
![30\ minutes=0.50\ hours](https://tex.z-dn.net/?f=30%5C%20minutes%3D0.50%5C%20hours)
![16.05+0.50=16.55\ hours](https://tex.z-dn.net/?f=16.05%2B0.50%3D16.55%5C%20hours)
Convert to minutes
![16.55\ h=16.55(60)\ min=993\ min](https://tex.z-dn.net/?f=16.55%5C%20h%3D16.55%2860%29%5C%20min%3D993%5C%20min)
step 3
Remember that
![8 p.m=20:00\ hrs](https://tex.z-dn.net/?f=8%20p.m%3D20%3A00%5C%20hrs)
Convert to minutes
![20(60)=1,200\ min](https://tex.z-dn.net/?f=20%2860%29%3D1%2C200%5C%20min)
Subtract 993 minutes from 1,200 minutes
![1,200-993=207\ min](https://tex.z-dn.net/?f=1%2C200-993%3D207%5C%20min)
Convert to hours+minutes
![207\ min=207/60=3.45\ hours](https://tex.z-dn.net/?f=207%5C%20min%3D207%2F60%3D3.45%5C%20hours)
![0.45\ h=0.45(60)=27\ min](https://tex.z-dn.net/?f=0.45%5C%20h%3D0.45%2860%29%3D27%5C%20min)
so
![3\ h+27\ min](https://tex.z-dn.net/?f=3%5C%20h%2B27%5C%20min)
![00:00 + 03:27=03:27\ am](https://tex.z-dn.net/?f=00%3A00%20%2B%2003%3A27%3D03%3A27%5C%20am)
therefore
The train need to leave Portland at 03:27 am
Answer:
X Company charges
more than Company Y
Step-by-step explanation:
Given:
Cost of X company = ![\$ 0.35+(\$0.05\times 1 \ minute)](https://tex.z-dn.net/?f=%5C%24%200.35%2B%28%5C%240.05%5Ctimes%201%20%5C%20minute%29)
Cost of Y Company =![\$ 0.15+(\$0.04\times 1 \ minute)](https://tex.z-dn.net/?f=%5C%24%200.15%2B%28%5C%240.04%5Ctimes%201%20%5C%20minute%29)
for n minutes
Cost of X company for n minutes = ![\$ 0.35+(\$0.05\times n \ minute)](https://tex.z-dn.net/?f=%5C%24%200.35%2B%28%5C%240.05%5Ctimes%20n%20%5C%20minute%29)
Cost of Y Company for n minutes =![\$ 0.15+(\$0.04\times n \ minute)](https://tex.z-dn.net/?f=%5C%24%200.15%2B%28%5C%240.04%5Ctimes%20n%20%5C%20minute%29)
Difference for n minutes we get by Subtracting Cost of Y Company for n minutes by Cost of X company for n minutes
Difference for n minutes =
=![(0.2+0.01n)\times 10^2 \ cents](https://tex.z-dn.net/?f=%280.2%2B0.01n%29%5Ctimes%2010%5E2%20%5C%20cents)
X Company charges
more than Company Y