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Dmitriy789 [7]
3 years ago
5

I am between 7,000,000 and 8,000,000. all my digits are odd. all the digits in my thousands period are the same. the sum of my d

igit is 31. what number am i? give as many answers as you can. what strategies did you use to find the mystrey number
Mathematics
2 answers:
lozanna [386]3 years ago
7 0

Answer:

The number can be many numbers like: 7,777,111  or 7,555,333  or 7,111,777

A: 7,777,111

We have four 7's and three 1's

7*4=28

1*3=3

28+3=31

B: 7,555,333

We have one 7, three 5's and three 3's.

5*3=15

3*3=9

15+9+7=31

These also can be 7,333,555 or 7,111,777.

aniked [119]3 years ago
4 0
There are many possibilities so I am going to give 3 answers 777113 777131 777311
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Brian spends 1/3 on his wages on rent and 1/4 on food. If he makes £576 per week, how much money does he have left
natta225 [31]

Answer:

Step-by-step explanation:

Money spent on rent =1/3 of $576= 1/3×576= $192

Money spent on food = 1/4 of 576 = 1/4×576 =$144

Money left = 576-(192+144)=

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6 0
3 years ago
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Use the equation 2,401 = 76 – 2x. What power of 7 is 2,401?
zaharov [31]
Comment
I'm going to take a guess at this and say what you meant is  2401 = 7^(6 - 2x)

Step One
Find out the power of 7 that will equal 2401. 
You could do it like this.
7^y = 2401 and just guess at some values.

y      7^y
1      7
2      49
3      7 * 7 * 7 = 343
4      7 * 7 * 7 * 7 = 2401  So the answer is 4

7^4 = 2401

Step 2 
Equate the powers.
2401 = 7^(6 - 2x)
7^4 = 7^ (6 - 2x)
4 = 6 - 2x  Subtract 6 from both sides.
4 - 6 = - 2x 
-2 = - 2x divide by - 2
-2/-2 = x
x = 1 <<<<<<<<<<<<<answer

7 0
4 years ago
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Which of the following statements must be true about this diagram?<br> Check all that apply.
Alik [6]

Answer:

i would go for a and c

Step-by-step explanation:

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