I don't know about the circle, but from the way it looks, you can use pythagorean theorem (A^2+B^2=C^2). angle E would be the Right Angle making 65=C or in other words, the hypotenuse, with 60 and Line ED being the legs (it doesn't matter which is A and which is B) leaving the equation
60^2+B^2=65^2 and solve from there. (if you need help solving, leave a comment and i will walk you through it in the comments)
The equation would be: Y= 1/2x-1. Reasoning: Our equation format is Y=mx+b. Consider y to just be there for the mean time, but mx is where we insert our slope. We already know what our slope is in this equation (1/2) so that’s what we’ll insert, changing mx to 1/2x. B is where we put our Y. In this coordinate, our Y is -1 (keep in mind that a coordinate is set up as so: (x,y). Insert all our numbers to replace the variables and you get Y=1/2x-1
Copy this for part A & B, the x-axis is (1.5,0) the y-axis is (0,1)
Area of the triangle = 1/2 x 2.9 x 8 = 11.6 cm²
Volume = base area x height
Volume = 11.6 x 6 = 69.6cm³
