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Vinil7 [7]
3 years ago
14

Please help me, this is confusing..

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
7 0
Copy this for part A & B, the x-axis is (1.5,0) the y-axis is (0,1)

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The inverse of the function graphed below is a function.?<br> A. True<br> B. False
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Step-by-step explanation:

A,true

doesn't interfere with any function restriction

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Michelle buys a rug for $36 and sells it for $90. What was the value of her markup, expressed as a percent?
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Her markup was about 60%.
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Ms. Reynold's sprinkler system has 5 stations that water all parts of her front and back lawn. Each station runs for an equal am
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Answer: 40 minutes

Step-by-step explanation:

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Multiply the polynomials (5x^2+4x-4)(4x^3-2x+6)<br> Explain your steps!!
Lapatulllka [165]
So distribute using distributive property
a(b+c)=ab+ac so

split it up
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group like terms
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the asnwer is 20x^5+16x^4-26x^3+22x^2+32x-24




4 0
3 years ago
WILL GIVE BRAINLIEST&amp; 15 PTS.
kicyunya [14]

Answer:

The given fraction \frac{x^3-x^2}{x^3} reduces to  \frac{x-1}{x}

Step-by-step explanation:

Consider the given fraction \frac{x^3-x^2}{x^3}

We have to reduce the fraction to the lowest terms.

Consider numerator x^3-x^2

We can take x² common from both the term,

Thus, numerator can be written as x^2(x-1)

Given expression can be rewritten as ,

\frac{x^3-x^2}{x^3}=\frac{x^2(x-1)}{x^3}

We can now cancel x^2 from both numerator and denominator,

\Rightarrow \frac{x^2(x-1)}{x^3}=\frac{x^2(x-1)}{x^2 \cdot x}

\Rightarrow \frac{(x-1)}{x^2 \cdot x}=\frac{x-1}{x}

Thus, the given fraction \frac{x^3-x^2}{x^3} reduces to  \frac{x-1}{x}

6 0
3 years ago
Read 2 more answers
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