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3 years ago

Answer question 2 and 3 plz I need help on this

Mathematics

2 answers:

Aneli [31]3 years ago

8 0

The answer to it is 0

trasher [3.6K]3 years ago

7 0

The answer to this question is zero

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In Simplest Form 1 1/4 ÷ 2 1/3=

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The answer is 5/24.

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3 years ago

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Rachel was cutting out some fabric for a friend. She cut a piece that was 5 centimeters wide and had an area of 20 cm power. how

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4 cm, 5 times 4 equals 20

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3 years ago

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Jack bought 5 pounds of halloween candy. he gave out 3 pounds of the candy to trick or treaters and ate 10 ounces of the candy .

Blababa [14]

Answer:

1 pound 6 ounces

Step-by-step explanation:

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1 year ago

What is the equation of the line through (4, 2) and (0, -2)?

satela [25.4K]

Answer:

Slope Intercept Form

y=x-2

Step-by-step explanation:

Find Slope using equation below

$\frac{y2 - y1}{x2 - x1}$

Chose points I chose 2 as y2 and -2 as y2

4 is x2 and 0 as x1

$\frac{2 - ( - 2)}{4 - 0} = \frac{4}{4} = 1$

Slope is 1

now choose a point and plug it in for x and y and plug slope in Equation

$y = mx + b$

I chose (4,2)

$2 = 1(4) + b$

2=4+b

subtract 4 by both sides

-2=b

Slope Form

$y = mx + b$

So... y=x-2 is the answer

3 0

2 years ago

If you're good at logarithms please help me with question h and show full working out ty ;)

Tems11 [23]

Answer: $x=\frac{31}{2}$

Step-by-step explanation:

$2log_a(x+2)=log_a(x+9)+log_a(x-3)$

The first thing we are going to do is to get rid of the 2 in front of the first logarithm. To do this, we have the power property that says:

$log_aX^n=nlog_aX$

Basically, the number in front, is the power of the number in the middle.

Let's rewrite this.

$log_a(x+2)^2=log_a(x+9)+log_a(x-3)$

Now, in order to add logarithms with the same base (in this case "a"), we write the same base of the logarithm, and multiply their values.

$log_a(x+2)^2=log_a(x+9)(x-3)$

Multiply the parentheses.

$log_a(x+2)^2=log_a(x^2-3x+9x-27)$

Combine like terms;

$log_a(x+2)^2=log_a(x^2+6x-27)$

Solve the binomial on the left side.

$log_a(x^2+4x+4)=log_a(x^2+6x-27)$

When we have logarithms with same base, we equal their values.

$x^2+4x+4=x^2+6x-27$

Subtract $x^2$

$x^2-x^2+4x+4=x^2-x^2+6x-27\\4x+4=6x-27$

Subtract 6x

$4x-6x+4=6x-6x-27\\-2x+4=-27$

Subtract 4

$-2x+4-4=-27-4\\-2x=-31$

Divide by -2.

$x=\frac{-31}{-2}\\ x=\frac{31}{2}$

5 0

3 years ago