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Triss [41]
3 years ago
12

At 8am the temperature was 56°F by noon a storm had arrived and the temperature was 43°F which describes the change in the tempe

rature from 8am until noon?
a. 99°F
b.-13°F
c.13°F
d.-17°F
Mathematics
2 answers:
Bad White [126]3 years ago
6 0

Answer:

B

Step-by-step explanation:

GaryK [48]3 years ago
3 0

Answer:

b. -13

Step-by-step explanation:

The change in temperature will be the original temperature plus or minus x, the change between a temp and b temp, to equal what the temperature is now.

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F(x) = 2x3 + 7x2 – 4x – 5
qaws [65]

Answer:

Its 3

Step-by-step explanation:

7 0
3 years ago
A rain gutter is made from sheets of aluminum that are 18 inches wide by turning up the edges to form right angles. Determine th
mr Goodwill [35]
The answer is C. 4.5 in
7 0
3 years ago
Can anyone please help!!!
quester [9]

Answer:

Question 9

(a) The distance, Jalaj walks in one day is 4.4 km

(b) The amount Jalaj raises after walking for 22 km at the end of the 5 days is $8

Question 10

(b) The difference between the largest and smallest areas is 2,400 m²

Step-by-step explanation:

Question 9

(a) The distance Jalaj walks in 5 days = 22 km

Whereby Jalaj walks equal distance every day, we have;

The distance, Jalaj walks in one day = 22 km/5 days = 4.4 km/day

The distance, Jalaj walks in one day = 4.4 km

(b) The amount he raises for every kilometer he walks = $1.60

The amount he raises after walking for 22 km at the end of the 5 days = 5 × $1.60  = $8

Question 10

(b) The given side length of the square = 120 meters to the nearest 10 meters

Therefore;

The maximum dimension for the side length of the square = 120 + 10/2 = 125

The largest possible area of the square, A_l = 125 m × 125 m = 15,625 m²

The minimum dimension for the side length of the square = 120 m - 10 m/2 = 115 m

The smallest possible area of the square, A_s = 115 m × 115 m = 13,225 m².

The difference between the largest and smallest areas, A_l - A_s = 15,625 - 13,225 = 2,400 m².

8 0
3 years ago
There are 9 classes of 25 students each 4 teachers in two times as many chaperones as teachers each bus hold a total of 45 peopl
Tanya [424]

Answer:

Least number of bus require for trip = 5 buses (Approx)

Step-by-step explanation:

Given:

Total number of classes = 9

Number of student in each class = 25

Number of teacher = 4

Number of chaperones = Double of teacher

Bus hold = 45 people

Find:

Least number of bus require for trip

Computation:

Total number of student = 9 × 25

Total number of student = 225

Number of chaperones = 4 × 2

Number of chaperones = 8

Total people = 225 + 8 + 4

Total people = 237

Least number of bus require for trip = Total people / Bus hold

Least number of bus require for trip = 237 / 45

Least number of bus require for trip = 5.266

Least number of bus require for trip = 5 buses (Approx)

6 0
3 years ago
9x-2y=11 <br> 5x-2y=15 <br> what is the solution to the above system of equations<br> ASAP
natali 33 [55]

9x - 2y = 11 ... (i)

5x - 2y = 15 ... (ii)

Subtracting equation (ii) from (i) we get;

4x + 0 = -4

4x=-4 , x = -1

Replacing x = -1 in equation (i) we get;

9(-1) - 2y = 11

-9 - 2y = 11

-2y = 20

y = 20 ÷ -2 = -10

The solution to the system of equations is (-1,-10).

8 0
3 years ago
Read 2 more answers
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