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igor_vitrenko [27]
3 years ago
13

Find the upper quartile, lower quartile, interquartile range, and any outliers for each set of data. 11.3, 28.8, 7.1, 12.7, 19,

16.7, 25.6, 7.1, 17.7, 17.5, 11.3, 2.7, 15.3, 20.8, 15.8
a 17, 11.3, 7.7, no outliers


b.. 19, 11.3, 7.7, no outliers


c. 19, 11.3, 6.7, no outliers


d. 19, 11.3, 7.7, 2.7
Mathematics
1 answer:
max2010maxim [7]3 years ago
4 0

Answer:

b.. 19, 11.3, 7.7, no outliers

Step-by-step explanation:

Our set of data is = {11.3, 28.8, 7.1, 12.7, 19, 16.7, 25.6, 7.1, 17.7, 17.5, 11.3, 2.7, 15.3, 20.8, 15.8) when we sort the set from smallest to the biggest then

{2.7, 7.1, 7.1, 11.3, 11.3, 12.7, 15.3, 15.8, 16.7, 17.5, 17.7, 19, 20.8, 25.6, 28.8]

Median of the set is the middle value in the sorted set, which is 15.8

Upper quartile is the middle value between the median and the highest number of the set, which is 19

Lower quartile is the middle value between the median and the highest number of the set, which is 11.3

Interquartile Range is the distance between Upper quartile and Lower quartile, which is 7.7

Outliers are any number in the set which is smaller then  Lower Quartile - (1.5×Interquartile Range)  and higher than Upper Quartile+(1.5×Interquartile Range)

Lower Quartile - (1.5×Interquartile Range) = 11.3-(1.5×7.7) = -0.25

Upper Quartile+(1.5×Interquartile Range)  = 19+(1.5×7.7) = 30.55.

There is no such number in the set, therefore no outliers in the set

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The binomial distribution is given by, 
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