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ivolga24 [154]
2 years ago
6

Factor the expression completely. 7x - 4x2

Mathematics
1 answer:
GrogVix [38]2 years ago
8 0

Answer:

x (7-4x)

factor x out of 7x-4x^2

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Plz help me with this
Agata [3.3K]

Answer:

It's the first option.

Step-by-step explanation:

y = cos x transformed  to cos (x - π/2) moves  the graph  π/2 units to the right.

Multiplying by 3 to give 3 cos(x -  π/2)  stretches the graph 3 units parallel to the y-axis and adding 3 to this moves the graph up 3 units.

So the required equation is y = 3(cos x -  π/2) + 3.

3 0
2 years ago
A pharmacist has 30% and 60% iodine solutions on hand. How many liters of each iodine solution will be required to produce 6 lit
kkurt [141]

Answer:

4 liters of 60% solution; 2 liters of 30% solution

Step-by-step explanation:

I like to use a simple, but effective, tool for most mixture problems. It is a kind of "X" diagram as in the attachment.

The ratios of solution concentrations are 3:6:5, so I've used those numbers in the diagram. The constituent solutions are on the left; the desired mixture is in the middle, and the numbers on the other legs of the X are the differences along the diagonals: 6 - 5 = 1; 5 - 3 = 2. This tells you the ratio of 60% solution to 30% solution is 2 : 1.

These ratio units (2, 1) add to 3. We want 6 liters of mixture, so we need to multiply these ratio units by 2 liters to get the amounts of constituents needed. The result is 4 liters of 60% solution and 2 liters of 30% solution.

_____

If you're writing equations, it often works well to let the variable represent the quantity of the greatest contributor—the 60% solution. Let the volume of that (in liters) be represented by v. Then the total volume of iodine in the mixture is ...

... 0.60·v + 0.30·(6 -v) = 0.50·6

... 0.30v = 0.20·6 . . . . subtract 0.30·6, collect terms

... v = 6·(0.20/0.30) = 4 . . . . divide by the coefficient of v

4 liters of 60% solution are needed. The other 2 liters are 30% solution.

6 0
3 years ago
Goran runs 6 miles in 57 minutes how many miles does he run per minute?
Morgarella [4.7K]
57/6 = 1/x
57 = 6x
x = 0.11 miles per minute
4 0
3 years ago
31 cars are in a race. In how many different ways can cars finish in order in the top 4 positions?
cupoosta [38]

Answer:

755,160 ways

Explanation:

We're told that 31 cars are in a race.

Considering the order in which the cars can finish in the top 4 positions, any of the 31 cars can finish in the first position, any of the remaining 30 cars can finish in the second position, any of the remaining 29 cars can finish in the third position and any of the remaining 28 cars can finish in the fourth position, so the different numbers of ways can be determined as seen below;

31\times30\times29\times28=755,160\text{ ways}

8 0
1 year ago
Please help me please
yan [13]

7.50 times hours would be her pay then add the bonus x number of bouquets 

a = 7.50h +(bn)
6 0
3 years ago
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