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2 years ago

Factor the expression completely. 7x - 4x2

Mathematics

1 answer:

GrogVix [38]2 years ago

8 0

Answer:

x (7-4x)

factor x out of 7x-4x^2

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Find all values of x in the interval [0, 2π] that satisfy the equation. <br><br>6sin²(x) = 3

34kurt

Answer:

The solutions are π/4, 3π/4,5π/4,7π/4

Step-by-step explanation:

The given equation is

6sin²(x) = 3

Divide by 6 to get:

${ \sin}^{2} (x) = \frac{1}{2}$

This implies that;

$\sin(x) = \pm \frac{ \sqrt{2} }{2}$

$\sin(x) = \frac{ \sqrt{2} }{2}$

$x = \frac{\pi}{4}$

in the first quadrant

$x = \frac{3\pi}{4}$

in the second quadrant.

$\sin(x) = - \frac{ \sqrt{2} }{2}$

$x = \frac{5\pi}{4}$

in the third quadrant

$x = \frac{7\pi}{4}$

5 0

3 years ago

Susan has completed 30 math problems, which is 3/5 of her homework assignment. How many problems were assigned for homework?

taurus [48]

50 problems were assigned <span />

6 0

3 years ago

Enter the ordered pair for point A in the boxes.

allsm [11]

-1.5, 2.5
X Y

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6 0

3 years ago

A triangle has angles that measure 54.6° and 17.8°. Which equation can be used to find the value of x, the measure of the third

Crazy boy [7]

Answer:

58.6 + 17.8 + x = 180

Step-by-step explanation:

hope this helps

6 0

3 years ago

Your favorite team is in the World Series. You have assigned a probability of 63% that they will win the championship. Past reco

frozen [14]

Answer:

0.3950

Step-by-step explanation:

Any team team will win the championship with probability 63% that is

P(W)=0.63

when teams win the championship, they win the first game of the series 72% of the time that is

P(F|W)=0.72

When they lose the championship, they win the first game 27% of the time.

P(F|W')=0.27

The probability that they will win the World Series when the first game is over and your team has lost that is

P(W|F')

Now, By Bayes theorem

$\begin{array}{l}P\left(W | F^{\prime}\right)=\frac{P\left(F^{\prime} | W\right) P(W)}{P\left(F^{\prime} | W\right) P(W)+P\left(F^{\prime} | W^{\prime}\right) P\left(W^{\prime}\right)} \\\quad=\frac{[1-P(F | W)] P(W)}{[1-P(F | W)] P(W)+\left[1-P\left(F | W^{\prime}\right)\right][1-P(W)]} \\\quad=\frac{[1-0.72] \times 0.63}{[1-0.72] \times 0.63+[1-0.27][1-0.63]} \\\quad=\frac{0.28\times 0.63}{0.28\times 0.63+0.73 \times 0.37} \\=0.3950\end{array}$

5 0

3 years ago