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Sauron [17]
3 years ago
11

Identify the area of the trapezoid. options: 299cm^2 325cm^2 425cm^2 399cm^2

Mathematics
2 answers:
shtirl [24]3 years ago
8 0

Answer:399

Step-by-step explanation:

((a+b)/2) * h

((13+25)/2) * 21

399

<!> Brainliest is appreciated! <!>

puteri [66]3 years ago
5 0
Answer: 399 cm^2

The formula is: (Top + Bottom)(height)/2

Therefore:
(13 + 25)(21)/2
= (38)(21)/2
= 798/2
= 399
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Marina’s bread recipe calls for 2/3 of a cup of flour. Which amount of flour represents the same amount?
Montano1993 [528]

Answer:

4/6

Step-by-step explanation:

this is going to be your answer because 2/6 is 1/3 cup and then 4/6 is 2/3 of a cup.

5 0
3 years ago
How do you find the length of a diagonal right triangle ?
V125BC [204]
Unsure what you mean by diagonal right triangle

but if you wanted to find the hypothenuse (longest side) of a right triangle, you can apply pythagorean theorem

a^2+b^2=c^2
where c is the hypothenuse
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7 0
3 years ago
11. If Sally
Delvig [45]

Answer:

0.2

Step-by-step explanation:

Multiply 4/5 and 1/4: Decimal form

.8 • .25

3 0
3 years ago
The temperature at noon was 88°f. By 4 p.M., the temperature was 27°f. Determine the constant rate of change of the temperature.
yawa3891 [41]

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8 0
3 years ago
Solve the system by using elementary row operations on the equations. Follow the systematic elimination procedure
Umnica [9.8K]

Answer:

The solution of the Given matrix

  ( x₁ ,    x ₂ ) = ( - 5 , 4 )

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given equations are  x₁+4 x₂ = 11 ...(i)

                                 2 x₁ + 7 x₂= 18 ...(ii)

The matrix form

                                A X = B

            \left[\begin{array}{ccc}1&4\\2&7\\\end{array}\right]  \left[\begin{array}{ccc}x\\y\\\end{array}\right] = \left[\begin{array}{ccc}11\\8\\\end{array}\right]

<u>Step(ii):-</u>

      \left[\begin{array}{ccc}1&4\\2&7\\\end{array}\right]  \left[\begin{array}{ccc}x\\y\\\end{array}\right] = \left[\begin{array}{ccc}11\\8\\\end{array}\right]

The Augmented Matrix form is

[AB] = \left[\begin{array}{ccc}1&4&11\\2&7&18\\\end{array}\right]

Apply Row operations,  R₂ → R₂-2 R₁

[AB] = \left[\begin{array}{ccc}1&4&11\\0&-1&-4\\\end{array}\right]  

The matrix form

                   \left[\begin{array}{ccc}1&4\\0&-1\\\end{array}\right]  \left[\begin{array}{ccc}x\\y\\\end{array}\right] = \left[\begin{array}{ccc}11\\-4\\\end{array}\right]

The equations are

                     x₁ + 4 x₂ = 11 ...(a)

                         - x ₂ = - 4

                            x ₂ = 4

Substitute   x ₂ = 4 in equation (a)

                      x₁ + 4 x₂ = 11

                      x₁ = 11 - 16

                        x₁ = -5

<u>Final answer</u>:-

The solution of the Given matrix

  ( x₁ ,    x ₂ ) = ( - 5 , 4 )

7 0
3 years ago
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