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2 years ago

11

Write a word phrase for each algebraic expression 5(x-2)

1 answer:

givi [52]2 years ago

6 0

Five times the sum of x and negative two, or five times the difference of x and two

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The number of goals scored by a soccer team varies directly as the number of shots on goal. If the Lakeside Bears scored 4 goals

enot [183]

Since it varies directly, divide the number of shots by the number of goals:

48 shots / 4 goals = 12

This tells you they score a goal every 12 shots.

Multiply shots needed by number of goals:

12 x 3 = 36

They need 36 more shots to score 3 more goals.

6 0

2 years ago

What’s an equation for<br> Five times a number

aalyn [17]

Answer: 5 x ?

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Needed help for my math please

vesna_86 [32]

Answer:

see explanation

Step-by-step explanation:

(a)

$\frac{a}{a}$ = 1 ( any value divided by itself = 1 )

(b)

$\frac{a}{1}$ = a ( any value divide by 1 is the value itself )

(c)

$\frac{a}{b}$ × $\frac{c}{d}$ = $\frac{ac}{bd}$

The product of 2 fractions is the product of the numerators divided by the product of the denominators

(d)

$\frac{a}{b}$ ÷ $\frac{c}{d}$ = $\frac{ad}{bc}$

To divide 2 fractions, leave the first fraction, change division to multiplication and turn the second fraction upside down, that is

$\frac{a}{b}$ ÷ $\frac{c}{d}$ = $\frac{a}{b}$ × $\frac{d}{c}$ = $\frac{ad}{bc}$

(e)

$\frac{a}{d}$ + $\frac{b}{d}$ = $\frac{a+b}{d}$

Since the fractions have a like denominator, add the numerators leaving the denominator. This applies to subtraction also

(f)

$\frac{a}{d}$ - $\frac{b}{d}$ = $\frac{a-b}{d}$

See explanation for part (e)

6 0

3 years ago

The solid figure shown here can be formed from which net?

borishaifa [10]

Answer:

B

Step-by-step explanation:

If you unfold it you get shape B

5 0

3 years ago

Read 2 more answers

LCM of x<sup>2</sup>+5x+6 and x<sup>2</sup>-x-6 is ………………………

sergejj [24]

Answer:

$(x^2 - 9)(x + 2)$

Step-by-step explanation:

Given:

$x^2 + 5x + 6$

$x^2 - x - 6$

Required:

LCM of the polynomials

SOLUTION:

Step 1: Factorise each polynomial

$x^2 + 5x + 6$

$x^2 + 3x + 2x + 6$

$(x^2 + 3x) + (2x + 6)$

$x(x + 3) + 2(x + 3)$

$(x + 2)(x + 3)$

$x^2 - x - 6$

$x^2 - 3x +2x - 6$

$x(x - 3) + 2(x - 3)$

$(x + 2)(x - 3)$

Step 2: find the product of each factor that is common in both polynomials.

We have the following,

$x^2 + 5x + 6 = (x + 2)(x + 3)$

$x^2 - x - 6 = (x + 2)(x - 3)$

The common factors would be: =>

$(x + 2)$ (this is common in both polynomials, so we would take just one of them as a factor.

$(x + 3)$ and,

$(x - 3)$

Their product = $(x - 3)(x + 3)(x +2) = (x^2 - 9)(x + 2)$

4 0

3 years ago