Answer =3.333333333 is the answer
30cm divided by 9 cm to get ur answer
In this case it is recurring
Answer:
a) weight of the car = 2816,1 lbs
b) 2773 lbs
Step-by-step explanation:
The equilibrium force is 490 lbs. That force keep the car at rest, then
∑ Fy = 0 and ∑Fx = 0
Forces acting on the car:
The external force 490 lbs
weight of the car uknown
Normal force
sin∠10° = 0,174
cos∠10° = 0.985
∑Fx = 0 mg*sin10°- 490 = 0 ∑Fy = 0 mg*cos10° - N = 0
mg*0,174= 490
mg = 490 / 0,174
mg = 2816,1 lbs
weight of the car = 2816,1 lbs
The Normal force
mg*cos10° - N = 0 2816,1 * 0,985 = N
N = 2773 lbs
Then equal force in magnitude and in opposite direction will car exets on the driveway
Step-by-step explanation:
x = -2 and x = -5
x + 2 = 0 and x + 5 = 0
(x + 2)(x + 5) = 0
x² + 5x + 2x + 10 = 0
x² + 7x + 10 = 0
Option → B
Answer:
19
Step-by-step explanation:
Add up all the numbers:
3,2,2,2,1,1,1,4,2,1
Then you get 19.
Or you can say it as
3^2 + 2^4 + 1^4 + 4
