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3 years ago

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Larry has been paying the minimum balance on his three credit cards each month. He has outlined the minimum payments for the nex

t four months. He decides to snowball his debt after Month 1 according to the interest rate instead of paying the minimum payment. Part 1 (2 points): Explain, using complete sentences, how the total monthly payment will change for each month. Part 2 (2 points): Explain, using complete sentences, how the payments for each credit card will change for each month.

1 answer:

PSYCHO15rus [73]3 years ago

4 0

Answer:

cvgb

Step-by-step explanation:

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I NEED HELP PLEASE! ;0

Fittoniya [83]

Answer:

4:6 or 2:3

Step-by-step explanation:

Since the ratio of mass of oxygen to carbon is 4:3, when there are two carbons the ratio will be 4:3*2=4:6=2:3. Hope this helps!

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3 years ago

Use right triangle DCB to find the trig values for angle D.

n200080 [17]

Sin D= opp./hyp. = 35/37
cos D= adj./hyp. = 12/37
tan D= opp./ adj. = 35/12

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3 years ago

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The sum of two numbers is 28<br> and their product is 180.<br> Find the numbers.

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3 years ago

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I need help with this 9/2 divided by 2/9

wlad13 [49]

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20.25

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2 years ago

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The first term of a geometric sequence is 15, and the 5th term of the sequence is <img src="https://tex.z-dn.net/?f=%5Cfrac%7B24

sladkih [1.3K]

The geometric sequence is $15,9,\frac{27}{5},\frac{81}{25}, \frac{243}{125}$

Explanation:

Given that the first term of the geometric sequence is 15

The fifth term of the sequence is $\frac{243}{125}$

We need to find the 2nd, 3rd and 4th term of the geometric sequence.

To find these terms, we need to know the common difference.

The common difference can be determined using the formula,

$a_n=a_1(r)^{n-1}$

where $a_1=15$ and $a_5=\frac{243}{125}$

For $n=5$ , we have,

$\frac{243}{125}=15(r)^4$

Simplifying, we have,

$r=\frac{3}{5}$

Thus, the common difference is $r=\frac{3}{5}$

Now, we shall find the 2nd, 3rd and 4th terms by substituting $n=2,3,4$ in the formula $a_n=a_1(r)^{n-1}$

For $n=2$

$a_2=15(\frac{3}{5} )^{1}$

$=9$

Thus, the 2nd term of the sequence is 9

For $n=3$ , we have,

$a_3=15(\frac{3}{5} )^{2}$

$=15(\frac{9}{25} )$

$=\frac{27}{5}$

Thus, the 3rd term of the sequence is $\frac{27}{5}$

For $n=4$ , we have,

$a_4=15(\frac{3}{5} )^{3}$

$=15(\frac{27}{25} )$

$=\frac{81}{25}$

Thus, the 4th term of the sequence is $\frac{81}{25}$

Therefore, the geometric sequence is $15,9,\frac{27}{5},\frac{81}{25}, \frac{243}{125}$

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3 years ago