I need help with numbers 3,and 5 please?

For the living room one, you have an 11' wall, & a 2' 6" shelf.
First, we'll divide the length of both in half:
5' 6" wall, 1' 3" shelf
Now, subtract the two:
4' 3"
That's how far away the edge of the shelf needs to be from either corner of the wall to be centered.

For the second one:
We need to get all these numbers into the same formatting. I say we go fraction.
First guy got 13 out of 18
Second guy got .7 (repeating)
Third guy got 5/6
Ok, first, we'll turn .7 repeating into a fraction. This won't always work, because not all decimals will turn into a nice fraction. But this one will.
.7 (repeating) = 7/9
So we have:
13/18
7/9
5/6
Now, we can't compare these quite yet. They all need to have the same denominator. So, what's the LCM of the three denominators? 18, right?
The first one can be left alone, since it has a denominator of 18 already. The second one: multiply both numbers by 2, and we get 14/18. For the third: multiply everything by 3, and we get 15/18.
NOW let's compare them:
Jon: 13/18
Jim: 14/18
Joe: 15/18
It's now clear that Joe got the highest score.

5 0

4 years ago

Write an exponential function in the form y=ab^xy=ab x that goes through points (0, 3)(0,3) and (4,48).

umka21 [38]

Answer:

y = 3(2^x)

Step-by-step explanation:

Put the given point values in the equation and solve for 'a' and 'b'.

3 = a(b^0) = a . . . . . for x=0, y=3

The y-intercept has given us the value of 'a'.

__

The other point will tell us 'b'.

48 = a(b^4) = 3(b^4) . . . . . for x=4, y=48

16 = b^4 . . . . . . . . . . . . . . . divide by 3

2^4 = b^4 ⇒ b = 2

The exponential function is ...

y = 3(2^x)

_____

<em>Additional comment</em>

We can use roots to find b:

16^(1/4) = (b^4)^(1/4) = b

2 = b . . . . your calculator can do this, or √(√16) = 16^(1/4) = 2.

3 0

3 years ago

You are conducting a study to see if the proportion of men over the age of 50 who regularly have their prostate examined is sign

Furkat [3]

Answer:

1. Yes, the sample data provides convincing evidence to support the claim that the proportion of men over the age of 50 who regularly have their prostate examined is significantly less than 0.37

2. The correct hypotheses are;

The null hypothesis is H₀: p ≥ p₀

The alternative hypothesis is Hₐ: p < p₀

Step-by-step explanation:

given

The null hypothesis is H₀: p ≥ p₀ where p₀ = 0.37

The alternative hypothesis is Hₐ: p < p₀

The formula for the z test is presented as follows;

$z=\dfrac{\hat{p}-p_0}{\sqrt{\dfrac{p_0 (1 - p_0)}{n}}}$

Where:

$\hat p$ = Sample proportion = 206/780 = 0.264

p₀ = Population proportion = 0.37

n = Sample size = 780

α = Significance level = 10% = 0.01

Plugging in the values, we have;

$z=\dfrac{0.264-0.37}{\sqrt{\dfrac{0.37 (1 - 0.37)}{780}}} = -6.13$

From the the z relation/computation, we have the p value = 0.000000000451

Since the p value which is 0.000000000451 is less than α, which is 0.01 we reject the null hypothesis and we fail to reject the alternative hypothesis, that is there is sufficient statistical evidence to suggest that the proportion of men over the age of 50 who regularly have their prostate examined is significantly less than 0.37.

4 0

3 years ago