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sdas [7]
3 years ago
7

I need help with numbers 3,and 5 please?

Mathematics
1 answer:
LiRa [457]3 years ago
7 0
I know #3 is 2×2=4/5×5=25/7×7=49 but I dont know #4
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Each leg of a triangle measures 12 cm what is the length of the hypotenuse
alexira [117]
The legs are 12 cm each, so the hypotenuse is√(144+144)=12√2☺☺☺☺
6 0
3 years ago
Please help solve this system of equations
stepan [7]

Make a substitution:

\begin{cases}u=2x+y\\v=2x-y\end{cases}

Then the system becomes

\begin{cases}\dfrac{2\sqrt[3]{u}}{u-v}+\dfrac{2\sqrt[3]{u}}{u+v}=\dfrac{81}{182}\\\\\dfrac{2\sqrt[3]{v}}{u-v}-\dfrac{2\sqrt[3]{v}}{u+v}=\dfrac1{182}\end{cases}

Simplifying the equations gives

\begin{cases}\dfrac{4\sqrt[3]{u^4}}{u^2-v^2}=\dfrac{81}{182}\\\\\dfrac{4\sqrt[3]{v^4}}{u^2-v^2}=\dfrac1{182}\end{cases}

which is to say,

\dfrac{4\sqrt[3]{u^4}}{u^2-v^2}=\dfrac{81\times4\sqrt[3]{v^4}}{u^2-v^2}

\implies\sqrt[3]{\left(\dfrac uv\right)^4}=81

\implies\dfrac uv=\pm27

\implies u=\pm27v

Substituting this into the new system gives

\dfrac{4\sqrt[3]{v^4}}{(\pm27v)^2-v^2}=\dfrac1{182}\implies\dfrac1{v^2}=1\implies v=\pm1

\implies u=\pm27

Then

\begin{cases}x=\dfrac{u+v}4\\\\y=\dfrac{u-v}2}\end{cases}\implies x=\pm7,y=\pm13

(meaning two solutions are (7, 13) and (-7, -13))

8 0
3 years ago
What's 8.23+10.9 simplified?
Serggg [28]
It is going to be 18.32
7 0
3 years ago
Graph f(x)=3x+5 and g(x)=3x-2
IgorLugansk [536]

Answer:

Two parallel lines

Step-by-step explanation:

the slopes are the same: slope = 3

f(x) 3x + 5                          g(x) = 3x - 2

Pick at least three x values and find their corresponding values for y. Remember the f(x)  and g(x) represent y

                                   f(x) = 3x + 5                           g(x) = 3x - 2

                                    y = 3x + 5                              y = 3x - 2

let x = 0                       y = 3(0) + 5                              y = 3(0) - 2

                                     y = 5                                         y   =  -2

Ordered pair                (0, 5)                                        (0, -2)

Let x = 1                      y = 3(1) +5                                y  = 3(1) - 2

                                  y = 8                                         y = 1

ordered pair                (1, 8)                                        (1, 1)

Let x = -1                  y = 3(-1) + 5                               y = 3(-1) - 2                  

                                  y = 2                                        y =  -5

ordered pair             (-1, 2)                                         ( -1, -5)

Locate the ordered pairs and draw the graph on the lines.  

you will graph two parallel lines        

4 0
2 years ago
Solve for x.<br><br> 3x− 8 = −x −8
Harrizon [31]

Answer:

x=0

Step-by-step explanation:

Cancel -8 on both sides.

3x=−x

Subtract -x from both sides.

3x+x=0

Simplify  3x+x  to 4x.

4x=0

Divide both sides by 4

x=0

Brainliest please!

3 0
3 years ago
Read 2 more answers
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