How do you solve this equation 2x+5y=11 -3x+8y=-1

solmaris [256]

Answer:

B.

Step-by-step explanation:

For an expression to be a polynomial , it must contain no square roots of variables, no fractional or negative powers on the variables, and no variables in the denominators of any fractions.

7 0

3 years ago

Read 2 more answers

Why is everything 1 when raised to the 0th power?

olga_2 [115]

Yeah dang i have no idea. great question tho

3 0

3 years ago

Read 2 more answers

Help!

andre [41]

Answer:

∠X in the pre-image will be equal to ∠L in the main image

Step-by-step explanation:

△LMN is the result of a reflection of △XYZ which means △LMN is the mirror image △XYZ

hence, the left of △XYZ will be equivalent to the right of △LMN and the right of △XYZ will be equivalent to the left of △LMN

Hence, ∠X in the pre-image will be equal to ∠L in the main image

6 0

3 years ago

What is the answer to the equation x squared minus 2x equals 15.

anzhelika [568]

Answer:

$x = 5 \\ x = - 3$

Step-by-step explanation:

${x}^{2} - 2x = 15 \\ {x}^{2} - 2x - 15 = 0 \\ {x}^{2} + 3x - 5x - 15 = 0 \\ x(x + 3) - 5(x + 3) = 0 \\ (x - 5)(x + 3) = 0 \\ x - 5 = 0 \: \: \: \: \: or \: \: \: \: x + 3 = 0 \\ x = 5 \: \: \: \: or \: \: \: \: \: \: x = - 3$

7 0

3 years ago

Every day a kindergarten class chooses randomly one of the 50 state flags to hang on the wall, without regard to previous choice

Svet_ta [14]

Answer:

a.) P(x = X) = $\frac{1}{50}$

b.) $\frac{1}{50} \times\frac{1}{50} \times\frac{1}{50} = \frac{1}{125000}$

c.) 0.00118

Step-by-step explanation:

The sample space Ω = flags of all 50 states

a.) Any one of the flags is randomly chosen. Therefore we can write the

probability measure as P(x = X) = $\frac{1}{50}$ , for all the elements of the sample

space, that is for all x ∈ Ω.

b.) the probability that the class hangs Wisconsin's flag on Monday,

Michigan's flag on Tuesday, and California's flag on Wednesday

= $\frac{1}{50} \times\frac{1}{50} \times\frac{1}{50} = \frac{1}{125000}$

c.) the probability that Wisconsin's flag will be hung at least two of the three days

= Probability that Wisconsin's flag will be hung on two days + Probability that Wisconsin's flag will be hung on three days

= P(x = 2) + P(x = 3)

= $(\binom{3}{2}\times \frac{1}{50} \times \frac{1}{50}\times \frac{49}{50}) + (\binom{3}{3}\times \frac{1}{50} \times \frac{1}{50}\times \frac{1}{50})\\$

= $\frac{147}{125000} + \frac{1}{125000}$

= $\frac{148}{125000}$

= 0.00118

7 0

3 years ago