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Dvinal [7]
3 years ago
11

A pet store has 58 pounds of dry dog food in stock. This is about 7 times the number of pounds of dry cat food that the store ha

s in stock. About how many pounds of dry cat food does the store have?
Mathematics
1 answer:
Roman55 [17]3 years ago
6 0
They would have about 8 pounds of dry cat food…to be specific, 8 remainder 2
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14-9x=-8(10+x) slove and show check
larisa [96]
23x =14 this will be the answer
6 0
3 years ago
Find the distance between the two points rounding to the nearest tenth (if necessary).
Genrish500 [490]

Answer:

13 units

Step-by-step explanation:

(-1,5) and (4, -7)

To find the distance of two points, we use the distance formula:

d = \sqrt{(x_{2}-x_1)^2 + (y_2-y_1)^2 }

Let's plug in what we know.

d = \sqrt{(4 - (-1))^2 + (-7 - 5)^2 }

Evaluate the double negative.

d = \sqrt{(4 +1))^2 + (-7 - 5)^2 }

Evaluate the parentheses.

d = \sqrt{(5)^2 + (-12)^2 }

Evaluate the exponents.

d = \sqrt{(25) + (144) }

Add.

d = \sqrt{(169) }

Evaluate the square root.

d = 13

13 units

Hope this helps!

4 0
3 years ago
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Estimate the answer to the following calculation<br><br>​
ryzh [129]

\frac{7.4^2 +\sqrt{8.67}}{0.53} \approx \bold{108.876}\\

3 0
3 years ago
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If the endpoints of the diameter of a circle are (−6, 6) and (6, −2), what is the standard form equation of the circle?
Sergeeva-Olga [200]
<span>i  Ace</span>hello :
let : A(-6,6)  B(6,-2)
the center is w((-6+6)/2 , (6-2)/2)....(midel <span>[ AB]
w(0 ,2)
the ridus is : r = AB/2
AB = </span>√(-6-6)²+(6+2)² = √(144+64) =<span>√208/2
</span>an equation in <span>standard form equation of the circle :
</span>(x+0)²+(y-2)² =  (√208/2)²=208/4 = 52
4 0
3 years ago
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I NEED HELP PLEASE, THANKS! :)
NISA [10]

Answer:   \bold{b)\quad \dfrac{2\pi}{3},\dfrac{4\pi}{3},0}

<u>Step-by-step explanation:</u>

Note the following identities: tan² x = sec²x - 1

                                                 \sec x=\dfrac{1}{\cos}

tan² x + sec x = 1

(sec² x -1) + sec x = 1

sec² x + sec x - 2 = 0

(sec x + 2)(sec x - 1) = 0

sec x + 2 = 0     sec x - 1 = 0

sec x = -2          sec x = 1

\dfrac{1}{\cos x}=-2\qquad \dfrac{1}{\cos x}=1\\\\\cos x=-\dfrac{1}{2}\qquad \cos x=1\\\\x=\dfrac{2\pi}{3}, \dfrac{4\pi}{3}\qquad x=0

8 0
3 years ago
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