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3 years ago

11

A pet store has 58 pounds of dry dog food in stock. This is about 7 times the number of pounds of dry cat food that the store ha

s in stock. About how many pounds of dry cat food does the store have?

1 answer:

Roman55 [17]3 years ago

6 0

They would have about 8 pounds of dry cat food…to be specific, 8 remainder 2

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i am using my big brothers acount. i need help johnny got 10 apples and he had 10 dollars now he dosent have money. did he spend

Oxana [17]

Answer:

Yes. He spent 10 dollars.

Step-by-step explanation:

If he bought 10 apples, and he had 10 dollars, he would have no money left because each apple was 1 dollar.

hope this helps!

4 0

3 years ago

The domain of y = cosx is the set of real numbers. True False

artcher [175]

Answer:

true

Step-by-step explanation:

3 0

2 years ago

Let A= {a,b,c,d,e} and let B= {1,2,3,4,5} determine n(AxB)

777dan777 [17]

n(AxB) = 25

Step-by-step explanation:

AxB in sets is called Cartesian product. And is defined as a set of ordered pairs (a,b) where a belongs to A and b belongs to B.

Given

A = {a,b,c,d,e}

B = {1,2,3,4,5}

The number of elements for Cartesian product of two sets is determined by:

$n(AxB) = n(A) * n(B)$

Here

$n(A) = 5\\n(B) = 5$

So,

$n(AxB) = 5*5 = 25$

Hence,

n(AxB) = 25

Keywords: Sets, Cartesian Product

Learn more about sets at:

#LearnwithBrainly

7 0

3 years ago

Use theorem 7. 4. 2 to evaluate the given laplace transform. do not evaluate the convolution integral before transforming. (writ

irga5000 [103]

With convolution theorem the equation is proved.

According to the statement

we have given that the equation and we have to evaluate with the convolution theorem.

Then for this purpose, we know that the

A convolution integral is an integral that expresses the amount of overlap of one function as it is shifted over another function.

And the given equation is solved with this given integral.

So, According to this theorem the equation becomes the

$\mathscr{L} \left( \int_{0}^{t} e^{-\tau} \cos \tau d \tau \right) = \frac{ \mathscr{L} (e^{-\tau} \cos \tau ) }{s} \\\mathscr{L} \left( \int_{0}^{t} e^{-\tau} \cos \tau d \tau \right) = \frac{\frac{s+1}{(s+1)^2+1}}{s} \\\mathscr{L} \left( \int_{0}^{t} e^{-\tau} \cos \tau d \tau \right) = \frac{1}{s}\left (\frac{s+1}{(s+1)^2+1} \right).$

Then after solving, it become and with theorem it says that the

$\mathscr{L} \left( \int_{0}^{t} f(\tau) d\tau \right) = \frac{\mathscr{L} ( f(\tau))}{s} .$

Hence by this way the given equation with convolution theorem is proved.

So, With convolution theorem the equation is proved.

Learn more about convolution theorem here

brainly.com/question/15409558

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3 0

2 years ago

A train travels from Tutuban to Calamba station. The distance between Tutuban and Calamba is defined by the function d(x) = x4 +

svlad2 [7]

given :

d(x) = x^4 + x^3 + 3x^2 + 4x - x kilometers.

t(x) = x

presumably the same value of x is used in both equations.

distance traveled is a function of time traveled, and that this relationship is preserved for any given speed.

Formula

r × t = d

r is the rate in kilometers per hour.

t is the time in hours.

d is the distance in hours.

based on the formulas you are given, this becomes:

r * t(x) = d(x)

if the train travels for 2 hours, then:

t(x) = t(2) = 2

d(x) = x^4 + x^3 + 3x^2 + 4x - x

d(2) = 2^4 + 2^3 + 3*2^2 + 4*2 - 2

d(2) = 42.

hence, t(2) = 2 and d(2) = 42

if the trip takes 2 hours, then the distance traveled is 42 kilometers based on the value of x = 2 in both equations.

the rate * time = distance equation of r * t(x) = d(x)

r × 2 = 42

r = 42/2

= 21.

this says the train will travel 42 kilometers in 2 hours if the train travels at 21 kilometers per hour.

4 0

3 years ago