Given:
In a two-digit number, the tens digit is 5 less than the units digit.
The number itself is five more than three times the sum of its digits.
To find:
The number.
Solution:
Let the two digit number is ab. So,

Tens digit is 5 less than the units digit.
...(i)
The number itself is five more than three times the sum of its digits.



...(ii)
Using (i) and (ii), we get





Putting b=8 in (i), we get


Therefore, the required number is 38.
3x-10+x+8=90
4×-2=90
4x=92
X=23
One angle is 31. 23+8
The second one is 59. 3 (23)-10
Answer:
A=24in²
Step-by-step explanation:
129/43x100=300
129 is 43% of 300