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iVinArrow [24]
3 years ago
9

If a rock is thrown 0.8 meters into the air, How fast was it thrown

Chemistry
2 answers:
PIT_PIT [208]3 years ago
5 0

Answer:

Speed, s = 3.95 m/s

Explanation:

It is given that, a rock is thrown 0.8 meters into the air. We have to find the velocity with which it is thrown.  

Using conservation of mechanical energy as :

K_i+P_i=K_f+P_f

Initial potential energy at the ground is 0 and at maximum height the final kinetic energy is 0.

So,

\dfrac{1}{2}mv^2=mgh

v=\sqrt{2gh}

putting g = 9.8 m/s² and h = 0.8 m

v=\sqrt{2\times 9.8\times 0.8}    

v = 3.95 m/s

Hence, it was thrown with a speed of 3.95 m/s

sergiy2304 [10]3 years ago
3 0
V=0 m/s, u=?, a = 9.8 m/s² and s = 0.8 m
u²=2×9.8×0.8=15.68
<span>u=3.959 ≈ 3.96 m/s

</span>
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Which change of phase is most likely occurring in the beaker
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Answer:

Evaporation

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Heat makes molecules move and eventually evaporate.

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3 years ago
What is the mass of 0. 513 mol Al2O3? Give your answer to the correct number of significant figures. (Molar mass of Al2O3 = 102.
Margarita [4]

The mass of a 0.513 mol of Al2O3 is 52.33g.

HOW TO CALCULATE MASS:

The mass of a substance can be calculated by multiplying the molar mass of the substance by its number of moles. That is;

mass of Al2O3 = no. of moles of Al2O3 × molar mass of Al2O3

According to this question, there are 0.513 moles of Al2O3.

Mass of Al2O3 = 0.513 × 102

Mass of Al2O3 = 52.33g

Therefore, the mass of a 0.513 mol of Al2O3 is 52.33g.

Learn more about mass calculations at: brainly.com/question/8101390?referrer=searchResults

7 0
2 years ago
Reynolds number, for an aorta of 0.9-centimeter diameter, calculate the blood flow in liters per minute when the flow regime in
olga55 [171]

Answer:

Flow in liters per minute is 4 L/min

Explanation:

For this case, we have an aorta of 0.9 cm of diameter (D). Let's suppose an uniform and constant diameter for calculation purposes.  

D = (0.9 cm)(1m/100cm)

D = 0.009 m

It is required to calculate the blood flow in liters per minute when the flow regime changes from laminar to turbulent. Laminar flow is usually less than 2500 for Reynolds value, and Turbulent flow when Re is higher than 2500. So, we need to study the phenomenon for  

Re = 2500.

Using the definition of Reynolds we can find the velocity average of the blood, and use it to find flow. Where blood density is \rho, aorta diameter is D, average velocity is v and blood viscosity is \mu

Re = \frac{\rho v D}{\mu } \\v = \frac{Re*\mu}{\rho D}

From data problem, we have Re, D values. As we need blood density and blood viscosity we can find them in medical studies. For example: in this online document: Blood flow analysis of the aortic arch using computational fluid dynamics †  

Satoshi Numata, Keiichi Itatani, Keiichi Kanda, Kiyoshi Doi, Sachiko Yamazaki, Kazuki Morimoto, Kaichiro Manabe, Koki Ikemoto, Hitoshi Yaku Author Notes  

European Journal of Cardio-Thoracic Surgery, Volume 49, Issue 6, June 2016, Pages 1578–1585, https://doi.org/10.1093/ejcts/ezv459  

Published: 20 January 2016

\rho = 1060 kg/m^3\\\mu = 0.0004 kg/(ms)\\

v = \frac{Re*\mu}{\rho D}\\v = \frac{2500 * 0.004 kg/(ms)}{(1060 kg/m3)(0.009 m)}\\v = 1.04 m/s\\

Average blood velocity is 1.04 m/s. After that, we can calculate the flow (Q) using the flow are (Ao) of aorta.

Q = v*Ao

Q = (1.4m/s)*(\pi*(0.009m/2)^2)\\Q = 6.67 * 10^-5 \frac{m^3}{s}\\Q = (6.67 * 10^-5 \frac{m^3}{s})(\frac{1000 L}{1 m^3} ) (\frac{60 s}{1 min} )\\Q = 4 L/min

Finally, the blood flow in liters per minute is 4 L/min when the flow regime in the aorta changes from laminar to turbulent.

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Identify the role of all molecular constituents present in a functional polyribosome. Drag the terms on the left to the appropri
nikitadnepr [17]

A polyribosome (or polysome) is a complex of one mRNA molecule and two or more ribosomes that  form a polypeptide chain during active translation. Since multiple ribosomes can translate  mRNA simultaneously, many polypeptides can be produced simultaneously from a single mRNA.

<h3>Role of all molecular constituents present in a functional polyribosome ;</h3>

1. mRNA: contains the codon

2. tRNA : contains the anticodon for the mRNA

3. Ribosome (large & small subunits): facilitates interaction between mRNA and tRNA

4. Amino acids:

5. Initation Factors: proteins important in the interaction/binding of the small subunit, mRNA, TRNAmet, and the Shine Dalgarno sequence

7. Elongation Factors: bring charged tRNA's to the A site of the ribosome

8. GTP: provides energy

Ribosome recruitment in eukaryotes occurs when the eukaryotic initiation factor e1F4F and poly(A) binding protein (PABP) recognize 5′-capped mRNAs and recruit the 43S ribosome complex to this site. increase. In addition, the Kozak consensus sequence ACCAUGG is also required for translation initiation. Therefore, at first glance, it seems unlikely that  overlapping sequences will be translated.

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What is potential energy?
V125BC [204]

The energy possessed by a body by virtue of its position relative to others, stresses within itself, electric charge, and other factors.

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