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iVinArrow [24]
3 years ago
9

If a rock is thrown 0.8 meters into the air, How fast was it thrown

Chemistry
2 answers:
PIT_PIT [208]3 years ago
5 0

Answer:

Speed, s = 3.95 m/s

Explanation:

It is given that, a rock is thrown 0.8 meters into the air. We have to find the velocity with which it is thrown.  

Using conservation of mechanical energy as :

K_i+P_i=K_f+P_f

Initial potential energy at the ground is 0 and at maximum height the final kinetic energy is 0.

So,

\dfrac{1}{2}mv^2=mgh

v=\sqrt{2gh}

putting g = 9.8 m/s² and h = 0.8 m

v=\sqrt{2\times 9.8\times 0.8}    

v = 3.95 m/s

Hence, it was thrown with a speed of 3.95 m/s

sergiy2304 [10]3 years ago
3 0
V=0 m/s, u=?, a = 9.8 m/s² and s = 0.8 m
u²=2×9.8×0.8=15.68
<span>u=3.959 ≈ 3.96 m/s

</span>
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First you need to calculate the volume needed (done in the explanation), it is 16.6 mL. Using a graduated pipette one measures this volume and transfer it into a 2L volumetric flask that is already half filled with distilled water, and then one fills it until its mark.

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Each liter of a 0.500M solution has half mol, so 2L of said solution has 1 mol of salt. Sodium chloride molar mass is 58.44g/mol, so in 2L of solution there is 58.44g of salt. That`s the mass that`s going to be weighted and transferred to a 2L volumetric flask.

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This is the equation for dilution of solutions:

c_{1} v_{1} =c_{2} v_{2}

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5g of a mixture of KOH and KCl with water form a solution of 250mL. We have 25ml of this solution and we mix it with 14,3mL of H
cricket20 [7]
We know that the number of moles HCl in 14.3mL of 0.1M HCl can be found by multiplying the volume (in L) by the concentration (in M).
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Since the morality does not change when you take some of the solution away, we know that the 250mL solution also had a molarity of 0.0572.  That being said you can find the number of moles the mixture had by multiplying 0.0572M KOH by 0.250L to get the number of moles of KOH.
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Now you can find the mass of the KOH by multiplying it by its molar mass of 56.1g/mol.
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