Good idea!maybe I should try that
<span>Y-intercept of (0, −1), starts up on the left, gets closer to y = −3 on the right.
You have to plot the graph to see it. Google online graphing calculator and enter the equation.</span>
Answer:
2,2,4-trimethylpentane has the higher heat of combustion in kcal/mol.
Explanation:
Heat of combustion is defined as heat evolved on combustion of 1 mole of a substance.
2,2,4-trimethylpentane has the higher heat of combustion in kcal/mol.
Heat combustion of 2,2,4-trimethylpentane = (1304 kcal/mol) and

1 mole of 2,2,4-trimethylpentane on combustion gives 8 mole sof carbon dioxide gas and 9 moles of water.
Heat combustion of ethanol = (327 kcal/mol)

1 mole of ethanol on combustion gives 2 moles of carbon dioxide gas and 3 mole of water.
Heat combustion of ethanol < Heat combustion of 2,2,4-trimethylpentane
Salutations!
Which halogen is most likely to react?
Fluorine (F) is the halogen that is most likely to react.
Thus, your answer is B.
Hope I helped!