Question

5. The volleyball team has a double-header on Friday. The probability that they

Answer 1

Answer: 54.29%

Step-by-step explanation:

Given: The probability that they  will win both games is 38%.

i.e. P( both games will win) =0.38

The probability that they will win just the first game is  70%.

P(first game will win) = 0.70

To find : P(second game will win| first game will win)

Using formula: $P(B|A)=\dfrac{P(\text{both A and B})}{P(A)}$

So, P(second game will win| first game will win) = $\dfrac{\text{ P( both games will win)}}{\text{P(first game will win)}}$

$=\frac{0.38}{0.70}\approx0.5429=54.29\%$

Hence, the required probability = 54.29%